Two point charges of +2.0 µC and -6.0 µC are located on the x-axis at x = -1.0 cm and x = +2.0 cm respectively. Where should a third charge of +3.0-µC be placed on the +x-axis so that the potential at the origin is equal to zero? (*= 1/4xr, = 8,99 × 109 N - m²/c²). The unit of the answer is cm.
Two point charges of +2.0 µC and -6.0 µC are located on the x-axis at x = -1.0 cm and x = +2.0 cm respectively. Where should a third charge of +3.0-µC be placed on the +x-axis so that the potential at the origin is equal to zero? (*= 1/4xr, = 8,99 × 109 N - m²/c²). The unit of the answer is cm.
College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![Question 8
Two point charges of +2.0 µC and -6.0 µC are located on the x-axis at x = -1.0 cm and x = +2.0 cm
respectively. Where should a third charge of +3.0-µC be placed on the +x-axis so that the potential
at the origin is equal to zero? (*= 1/4xtrg = 8,99 × 109 N - m²/c2). The unit of the answer is cm.
Question 9
Two point charges of +1.0 µC and -2.0 µC are located 0.50 m apart. What is the minimum amount of
work needed to move the charges apart to double the distance between them?
(k= 1/4, = 8.99 × 10° N • m²/c²). The unit of the answer in mJ.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb886bcef-cd77-41ce-892e-fadadfa83690%2F0a7046a8-3306-44f6-9b6c-e058c9dd81c7%2F6z0l01q_processed.png&w=3840&q=75)
Transcribed Image Text:Question 8
Two point charges of +2.0 µC and -6.0 µC are located on the x-axis at x = -1.0 cm and x = +2.0 cm
respectively. Where should a third charge of +3.0-µC be placed on the +x-axis so that the potential
at the origin is equal to zero? (*= 1/4xtrg = 8,99 × 109 N - m²/c2). The unit of the answer is cm.
Question 9
Two point charges of +1.0 µC and -2.0 µC are located 0.50 m apart. What is the minimum amount of
work needed to move the charges apart to double the distance between them?
(k= 1/4, = 8.99 × 10° N • m²/c²). The unit of the answer in mJ.
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