Two point charges are fixed on the y axis: a negative point charge q₁ = -26 µC at y₁ = +0.19 m and a positive point charge q2 at y2 = +0.30 m. A third point charge q = +8.1 µC is fixed at the origin. The net electrostatic force exerted on the charge q by the other two charges has a magnitude of 30 N and points in the +y direction. Determine the magnitude of 92.

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Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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Two point charges are fixed on the y-axis: a negative point charge \( q_1 = -26 \, \mu C \) at \( y_1 = +0.19 \, m \) and a positive point charge \( q_2 \) at \( y_2 = +0.30 \, m \). A third point charge \( q = +8.1 \, \mu C \) is fixed at the origin. The net electrostatic force exerted on the charge \( q \) by the other two charges has a magnitude of \( 30 \, N \) and points in the \( +y \) direction. Determine the magnitude of \( q_2 \).

**Diagram Explanation:**

The diagram shows a vertical y-axis with the following components:

- Charge \( q_2 \) is located at \( y_2 = +0.30 \, m \) on the positive y-axis.
- Charge \( q_1 \) is located at \( y_1 = +0.19 \, m \) below \( q_2 \), also on the positive y-axis.
- Charge \( q \) is positioned at the origin, \( (0,0) \), on the y-axis.
- An arrow representing the net electrostatic force \( \vec{F} \) is pointing upward along the y-axis, indicating the force is in the \( +y \) direction.

**Input Fields:**

- Number: [ Input Field ]
- Units: [ Dropdown for unit selection ]

The task is to calculate the magnitude of charge \( q_2 \) using the given information.
Transcribed Image Text:Two point charges are fixed on the y-axis: a negative point charge \( q_1 = -26 \, \mu C \) at \( y_1 = +0.19 \, m \) and a positive point charge \( q_2 \) at \( y_2 = +0.30 \, m \). A third point charge \( q = +8.1 \, \mu C \) is fixed at the origin. The net electrostatic force exerted on the charge \( q \) by the other two charges has a magnitude of \( 30 \, N \) and points in the \( +y \) direction. Determine the magnitude of \( q_2 \). **Diagram Explanation:** The diagram shows a vertical y-axis with the following components: - Charge \( q_2 \) is located at \( y_2 = +0.30 \, m \) on the positive y-axis. - Charge \( q_1 \) is located at \( y_1 = +0.19 \, m \) below \( q_2 \), also on the positive y-axis. - Charge \( q \) is positioned at the origin, \( (0,0) \), on the y-axis. - An arrow representing the net electrostatic force \( \vec{F} \) is pointing upward along the y-axis, indicating the force is in the \( +y \) direction. **Input Fields:** - Number: [ Input Field ] - Units: [ Dropdown for unit selection ] The task is to calculate the magnitude of charge \( q_2 \) using the given information.
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