An infinite line of positive charge lies along the y axis, with charge density a = 2.20 µC/m. A dipole is placed with its center along the x axis at x = 23.0 cm. The dipole consists of two charges +10.0 pC separated by 2.00 cm. The axis of the dipole makes an angle of 40.0° with the x axis, and the positive charge is farther from the line of charge than the negative charge. Find the net force exerted on the dipole. F = N
An infinite line of positive charge lies along the y axis, with charge density a = 2.20 µC/m. A dipole is placed with its center along the x axis at x = 23.0 cm. The dipole consists of two charges +10.0 pC separated by 2.00 cm. The axis of the dipole makes an angle of 40.0° with the x axis, and the positive charge is farther from the line of charge than the negative charge. Find the net force exerted on the dipole. F = N
Related questions
Question
An infinite line of positive charge lies along the y axis, with charge density
? = 2.20 µC/m.
A dipole is placed with its center along the x axis at
x = 23.0 cm.
The dipole consists of two charges ±10.0 µC separated by 2.00 cm. The axis of the dipole makes an angle of 40.0° with the x axis, and the positive charge is farther from the line of charge than the negative charge. Find the net force exerted on the dipole.
![**Problem Statement:**
An infinite line of positive charge lies along the y-axis, with a charge density \(\lambda = 2.20 \, \mu\text{C/m}\). A dipole is placed with its center along the x-axis at \(x = 23.0 \, \text{cm}\). The dipole consists of two charges \( \pm 10.0 \, \mu\text{C} \) separated by \(2.00 \, \text{cm}\). The axis of the dipole makes an angle of \(40.0^\circ\) with the x-axis, and the positive charge is farther from the line of charge than the negative charge. Find the net force exerted on the dipole.
\[
\vec{F} = \, \_\_\_\_ \, \text{N}
\]
**Explanation:**
- **Line of Charge:** The line of charge is along the y-axis with a charge density (\(\lambda\)) of \(2.20 \, \mu\text{C/m}\).
- **Dipole:** Consists of two charges (\(+10.0 \, \mu\text{C}\) and \(-10.0 \, \mu\text{C}\)) separated by \(2.00 \, \text{cm}\).
- **Position:** The dipole's center is on the x-axis at \(x = 23.0 \, \text{cm}\).
- **Orientation:** The dipole's axis forms a \(40.0^\circ\) angle with the x-axis.
- **Configuration:** The positive charge is positioned farther from the y-axis than the negative charge.
- **Objective:** Calculate the net force on the dipole.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff90dea9d-9cdb-42ca-abaa-dad0efc4d5b4%2F92738726-d24c-4a43-999e-e890d15ebc22%2F3xtr6bb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
An infinite line of positive charge lies along the y-axis, with a charge density \(\lambda = 2.20 \, \mu\text{C/m}\). A dipole is placed with its center along the x-axis at \(x = 23.0 \, \text{cm}\). The dipole consists of two charges \( \pm 10.0 \, \mu\text{C} \) separated by \(2.00 \, \text{cm}\). The axis of the dipole makes an angle of \(40.0^\circ\) with the x-axis, and the positive charge is farther from the line of charge than the negative charge. Find the net force exerted on the dipole.
\[
\vec{F} = \, \_\_\_\_ \, \text{N}
\]
**Explanation:**
- **Line of Charge:** The line of charge is along the y-axis with a charge density (\(\lambda\)) of \(2.20 \, \mu\text{C/m}\).
- **Dipole:** Consists of two charges (\(+10.0 \, \mu\text{C}\) and \(-10.0 \, \mu\text{C}\)) separated by \(2.00 \, \text{cm}\).
- **Position:** The dipole's center is on the x-axis at \(x = 23.0 \, \text{cm}\).
- **Orientation:** The dipole's axis forms a \(40.0^\circ\) angle with the x-axis.
- **Configuration:** The positive charge is positioned farther from the y-axis than the negative charge.
- **Objective:** Calculate the net force on the dipole.
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 3 steps with 3 images
![Blurred answer](/static/compass_v2/solution-images/blurred-answer.jpg)