Two pith balls carrying equal charges are suspended from a common point by strings of equal length, the equilibrium separation between them is r. Now the strings are rigidly clamped at half the height. The equilibrium separation between the balls now become - A Z (+) (5) (3) ()
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Q: 9A= ostat C q0: 5nC = 15stat c At Dt Scm B 98=9stat C q6=3statc
A: The potential is given by V =k qr where, q is the charge and r is the distance.
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A: Given that: m=0.01 kgq=1.60 μC=1.60×10-6CL=1.80 mθ=70.0°E=260 V/m
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Q: The two pith balls in Figure 20-14 each have a mass of 1.0 g and equal charges. One pith ball is…
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Q: Coulomb's law for the magnitude of the force F between two particles with charges Q and Q' separated…
A: Given value--- q1 = -17.5 nC at x1 = - 1.715 m. q2 = 36.5 nC at x2 = at origin. q3 = 50.5 mC at x3…
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Q: Coulomb's law for the magnitude of the force F between two particles with charges Q and Q' separated…
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Q: Two point charges of mass m each are suspended in the gravitational field of the Earth by two…
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Q: What amount of energy does it take to assemble a charge configuration consisting of 3 points charges…
A: Given: The value of the charge is 6.75×10-6 C. The three charges are separated by a distance 0.163…
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- A dipole of moment p1 lies at the origin and a dipole of p2 lies at a point whose position vector is r. Determine the force between the two dipoles. For which orientation of the dipoles does the force maximize?How much work is required to set up the four-charge configuration of the figure if q = 3.59 pC, a = 74.0 cm, and the particles are initially infinitely far apart and at rest? +1 -9 +qDipole consisting of two equal but opposite point charges separated by a distance "2L". The magnitude either dipole charge is , "qd". A vector quantity called the Electric Dipole Moment Vector ,p ,is defined to have a magnitude p = (qd)(d) (d= separation distance of the dipole charges) and a unit vector direction pointing from negative to positve charge Find the dipole moment vector “p”
- One end of a light spring with force constant k = 125 N/m is attached to a wall, and the other end to a metal block with charge A 1.94 μC on a horizontal, frictionless table as shown in the figure. A second block with charge qB -3.52 μC is brought close to the first block. The spring stretches as the blocks attract each other so that at equilibrium, the blocks are separated by a distance d = 12.8 cm. What is the displacement x of the spring? Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. m ¦ 9A 6000000000000000 + 9A ¨¨¨¨¨¨¨¨ + |←x → ←——_—_d- == 9BA small metal sphere carrying a net charge of Q = -2.00 uC is held stationary by insulating supports. A second small metal sphere with a net charge of Q 2 = +7.80 uC and mass 1.50 g is is held 0.8 m away from the center of the first sphere. Assume the two spheres can be treated as point charges and that you can ignore gravity. If the second sphere is released, how fast will it be traveling when it is 0.6 m away from the center of the first sphere?Two charged point particles both of mass m = 1 g and q = 1 µC are on a horizontal surface without friction with each other by means of a spring of elastic constant k = 0.2 N / m, at rest it is negligible. Is requested a) Find the length of the spring for which the master is in equilibrium b) Calculate the energy that is needed to stretch the spring from the length it has when the system is in equilibrium until it is one meter c) From this last position in which the distance between the charges is one meter and starting from rest, the charges are allowed to move, would they come closer to each other until the distance that separates them is 10 cm? if they don't explain why. If they do find the velocity of the charges when they reach that distance.
- Two point charges of mass m each are suspended in the gravitational field of the Earth by two non-conducting massless strings, each of length 1, attached to the same fixed point. The spheres are given equal charges Q of the same sign. As a result each string makes angle a to the vertical (see figure below). Calculate m, if 1 = 78.3 cm, Q = 4 µC and a = π/6. Take Coulomb constant ke-8.99×109 Nm² C-2. Give your answer in grams. / / / / L d MTwo point charges of mass m each are suspended in the gravitational field of the Earth by two non-conducting massless strings, each of length 7, attached to the same fixed point. The spheres are given equal charges Q of the same sign. As a result each string makes angle a to the vertical (see figure below). Calculate m, if I = 82.1 cm, Q = 4 µC and a = /6. Take Coulomb constant k = 8.99x109 N m² C-2. Give your answer in grams. 11 // e M 7 /// C d e MTwo identical point charges, with charge "+q", are fixed and separated by a distance "d". A third charge "-Q" of mass "m" can move freely and is at rest on the x-axis at the beginning in a distance of "X". How fast will the charge "-Q" move when it's at the middle of the charges "+q", if it's released from a distance x<