Two pieces of metal (A and B) are in contact with each other and initially at different temperatures. Metal A has a mass of 7.50 grams and an initial temperature of 24°C and metal B has a mass of 12.25 grams and an initial temperature of 51°C. When the two metals reach thermal equilibrium they have a final temperature of 35°C. If metal A has a specific heat capacity of 1.25 J/g°C what is the specific heat capacity of metal B?
Two pieces of metal (A and B) are in contact with each other and initially at different temperatures. Metal A has a mass of 7.50 grams and an initial temperature of 24°C and metal B has a mass of 12.25 grams and an initial temperature of 51°C. When the two metals reach thermal equilibrium they have a final temperature of 35°C. If metal A has a specific heat capacity of 1.25 J/g°C what is the specific heat capacity of metal B?
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Transcribed Image Text:Two pieces of metal (A and B) are in contact with each other and initially at different temperatures. Metal A has a mass of 7.50 grams and an initial temperature of 24°C, and metal B has a mass of 12.25 grams and an initial temperature of 51°C. When the two metals reach thermal equilibrium, they have a final temperature of 35°C. If metal A has a specific heat capacity of 1.25 J/g°C, what is the specific heat capacity of metal B?
Remember:
- \(-q\) for metal A = \(q\) for metal B and \(q = ms\Delta T\)
Do not type units with your answer.
Type your answer to three significant figures.
If this question is on an exam on your scrap paper, report your answer to the proper number of significant figures but still type three significant figures online.
Your Answer: _______________
Expert Solution
Step 1
For Metal A:
mass of metal A = 7.50 g
Initial Temperature = 24 oC
Final Temperature = 35 oC
Change in Temperature () = (35 oC - 24 oC ) = 11 oC
Specific heat capacity of metal A = 1.25 J/g oC
For Metal B:
mass of metal B = 12.25 g
Initial Temperature = 51 oC
Final Temperature = 35 oC
Change in Temperature () = ( 35 oC - 51 oC ) = -16 oC
Let Specific heat capacity of metal B = x
Where, q = Heat
m = mass
s = Specific heat capacity
= Change in Temperature
For metal A :
For metal B:
Here, heat gained by metal A = heat loss by metal B
Therefore, qA = - qB
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