Two meters below the ground surface, a 2x2 m square footing is constructed on NC clayey sand.The layer is subjected to a CPT test, with the results revealing an average cone resistance of 20Mpa. A layer of hard rock is laid 20 meters below the surface. The service load of 25 ton.f is actingon the footing column. Find the elastic settlement using the generalized elastic method. Thewater level is at the surface and you can use yw = 10 KN/m3. (footing weight is negligible)Hint: use table 4.8 of textbook to find the undrained modulus. TABLE 4.8 ESTIMATING EQUIVALENT SOIL MODULUS, ES, VALUES FROM CPT RESULTS[Adapted from Schmertmann et al. (1978), Robertson and Campanella (1989), and other sources.]USCS Group SymbolEslacSoil TypeYoung, normally consolidated clean silica sands (age < 100 years)Aged, normally consolidated clean silica sands (age > 3,000 years)Overconsolidated clean silica sandsNormally consolidated silty or clayey sandsOverconsolidated silty or clayey sandsSW or SPSW or SPSW or SPSM or SCSM or SC2.5-3.53.5-6.06.0-10.01.53

Two meters below the ground surface, a 2x2 m square footing is constructed on NC clayey sand. The layer is subjected to a CPT test, with the results revealing an average cone resistance of 20 Mpa. A layer of hard rock is laid 20 meters below the surface. The service load of 25 ton.f is acting on the footing column. Find the elastic settlement using the generalized elastic method. The water level is at the surface and you can use Yw = 10 KN/m3. (footing weight is negligible) Hint: use table 4.8 of textbook to find the undrained modulus.

Two meters below the ground surface, a 2x2 m square footing is constructed on NC clayey sand. The layer is subjected to a CPT test, with the results revealing an average cone resistance of 20 Mpa. A layer of hard rock is laid 20 meters below the surface. The service load of 25 ton.f is acting on the footing column. Find the elastic settlement using the generalized elastic method. The water level is at the surface and you can use Yw = 10 KN/m3. (footing weight is negligible) Hint: use table 4.8 of textbook to find the undrained modulus.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

100%

Two meters below the ground surface, a 2x2 m square footing is constructed on NC clayey sand.
The layer is subjected to a CPT test, with the results revealing an average cone resistance of 20
Mpa. A layer of hard rock is laid 20 meters below the surface. The service load of 25 ton.f is acting
on the footing column. Find the elastic settlement using the generalized elastic method. The
water level is at the surface and you can use yw = 10 KN/m3. (footing weight is negligible)
Hint: use table 4.8 of textbook to find the undrained modulus.

TABLE 4.8 ESTIMATING EQUIVALENT SOIL MODULUS, ES, VALUES FROM CPT RESULTS
[Adapted from Schmertmann et al. (1978), Robertson and Campanella (1989), and other sources.]
USCS Group Symbol
Eslac
Soil Type
Young, normally consolidated clean silica sands (age < 100 years)
Aged, normally consolidated clean silica sands (age > 3,000 years)
Overconsolidated clean silica sands
Normally consolidated silty or clayey sands
Overconsolidated silty or clayey sands
SW or SP
SW or SP
SW or SP
SM or SC
SM or SC
2.5-3.5
3.5-6.0
6.0-10.0
1.5
3

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Please answer question 3b Question 3b
For the following statements: P: The lateral stress in the soil while being tested in an oedometer is always at-rest. Q: For a perfectly rigid strip footing at deeper depths in a sand deposit, the vertical normal contact stress at the footing edge is greater than that at its centre. R: The corrections for overburden pressure and dilatancy are not applied to measured SPT-N values in case of clay deposits. The correct combination of the statements is P Q R (a) True True False (b) False (c) False False True False False (d) True True True
A2