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Two masses, m, and m2 are separated by a distance, r. The force of attraction between the two masses is F. If m, increases by 8, how does F change? 64 F (64 times the force) 1/8F (1/8 the force) 8F (8 times the force) 1/64F (1/64 the force)

Two masses, m, and m2 are separated by a distance, r. The force of attraction between the two masses is F. If m, increases by 8, how does F change? 64 F (64 times the force) 1/8F (1/8 the force) 8F (8 times the force) 1/64F (1/64 the force)

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Gravitational Force Calculation** Two masses, \( m_1 \) and \( m_2 \), are separated by a distance, \( r \). The force of attraction between the two masses is given by: \[ F_g = \frac{G m_1 m_2}{r^2} \] Where: - \( F_g \) is the gravitational force, - \( G \) is the gravitational constant, - \( m_1 \) and \( m_2 \) are the masses, - \( r \) is the distance between the centers of the two masses. **Problem Statement:** If \( m_1 \) increases by a factor of 8, how does the gravitational force \( F \) change? **Options:** - ○ 64 F (64 times the force) - ○ 1/8 F (1/8 of the force) - ○ 8 F (8 times the force) - ○ 1/64 F (1/64 of the force)
Transcribed Image Text:**Gravitational Force Calculation** Two masses, \( m_1 \) and \( m_2 \), are separated by a distance, \( r \). The force of attraction between the two masses is given by: \[ F_g = \frac{G m_1 m_2}{r^2} \] Where: - \( F_g \) is the gravitational force, - \( G \) is the gravitational constant, - \( m_1 \) and \( m_2 \) are the masses, - \( r \) is the distance between the centers of the two masses. **Problem Statement:** If \( m_1 \) increases by a factor of 8, how does the gravitational force \( F \) change? **Options:** - ○ 64 F (64 times the force) - ○ 1/8 F (1/8 of the force) - ○ 8 F (8 times the force) - ○ 1/64 F (1/64 of the force)
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