Two kg of refrigerant R134a, initially at P₁ = 1 MPa, u₁ = 312.70 kJ/kg, is con well-sealed copper tank. A paddle wheel is fitted into the tank to transfer e refrigerant at constant rate of 0.1 kW. The refrigerant loses heat to its surro rate K.t², in kW, where K is a constant, in kW per minute squared, and t is ti After 10 minutes of stirring, the refrigerant is at p2 = 0.6 MPa and U₂ = = 231.C overall changes in kinetic and potential energy occur. (a) For the refrigerant

Elements Of Electromagnetics
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Two kg of refrigerant R134a, initially at P₁ = 1 MPa, u₁ = 312.70 kJ/kg, is contained within a
well-sealed copper tank. A paddle wheel is fitted into the tank to transfer energy to the
refrigerant at constant rate of 0.1 kW. The refrigerant loses heat to its surroundings at a
rate K-t2, in kW, where K is a constant, in kW per minute squared, and t is time, in minutes.
After 10 minutes of stirring, the refrigerant is at p2 = 0.6 MPa and u₂ = 231.05 kJ/kg. No
overall changes in kinetic and potential energy occur. (a) For the refrigerant, determine the
work and heat transfer, each in kJ. (b) Determine the value of the constant K appearing in
the given heat transfer relation, in kW/min².
Transcribed Image Text:Two kg of refrigerant R134a, initially at P₁ = 1 MPa, u₁ = 312.70 kJ/kg, is contained within a well-sealed copper tank. A paddle wheel is fitted into the tank to transfer energy to the refrigerant at constant rate of 0.1 kW. The refrigerant loses heat to its surroundings at a rate K-t2, in kW, where K is a constant, in kW per minute squared, and t is time, in minutes. After 10 minutes of stirring, the refrigerant is at p2 = 0.6 MPa and u₂ = 231.05 kJ/kg. No overall changes in kinetic and potential energy occur. (a) For the refrigerant, determine the work and heat transfer, each in kJ. (b) Determine the value of the constant K appearing in the given heat transfer relation, in kW/min².
Expert Solution
Step 1

Given data as per questionMass of refrigerant, m=2 kgP1=1 MPa, u1=312.7 kJ/kgW˙=0.1 kWQ˙=k t2, where, kkW/min2After, t=10 minP2=0.6 MPa, u2=231.05 kJ/kgand KE=PE=0

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