Two identical point charges, P and Q, separated by a distance r, repel each other with a force F. If r is increased so that the electrical potential energy of Q is halved, what is the force of repulsion? ABCD ½ F F 2 F 14 F
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A: ∆EK=Ui-Uf=kqQri-kqQrf=kqQ1ri-1rf=9×109 NC5.5×10-6 C49.1×10-6 C119.3×10-2 m-119.3+95.1×10-2 m=10.47 J
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A: We’ll answer the first question since the exact one wasn’t specified. Please submit a new question…
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A: Q1=2.2×10-6C Length of square=0.45m Test charge q0=-3.1×10-8C Mass of test charge =9.4×10-8kg
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