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Two identical capacitors are of 1,474 x 10-6 F are connected in series. They store a total of 66.2 x 10-3 J of energy when connected to a source potential when fully charged.  These same two capacitors are discharged, then reconnected in parallel in the circuit with the same source potential. What total energy is stored by the system?

Two identical capacitors are of 1,474 x 10-6 F are connected in series. They store a total of 66.2 x 10-3 J of energy when connected to a source potential when fully charged.  These same two capacitors are discharged, then reconnected in parallel in the circuit with the same source potential. What total energy is stored by the system?

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Two identical capacitors are of 1,474 x 10-6 F are connected in series. They store a total of 66.2 x 10-3 J of energy when connected to a source potential when fully charged.  These same two capacitors are discharged, then reconnected in parallel in the circuit with the same source potential. What total energy is stored by the system?

 
Expert Solution
Step 1

Let C1 and C2 be defined as the capacitance of the individual capacitor, which is the same for both.

Let C be defined as the total capacitance. Let V be defined as the potential difference. Then the energy (U) be defined as,

U=CV

Step 2

Now given the stored energy when capacitors are connected in series. Therefore, the potential difference be calculated as,

U=CVU=C1C2C1+C2V                     ∵C=C1C2C1+C266.2×10-3 J=1474×10-6 F1474×10-6 F1474×10-6 F+1474×10-6 FV66.2×10-3 J=2172672×10-12 F22948×10-6 FV66.2×10-3 J=736.99×10-6 VV=0.08982×103 VV≃89.82 V

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