Two horizontal forces act on a 2.8 kg chopping block that can slide over a frictionless kitchen counter, which lies in an xy plane. One force is 1 = (3.2 N) + (3.8 N). Find the acceleration of the chopping block in unit-vector notation for each of the following second forces. (a) 2 = (−3.2 N) + (−3.8 N) = m/s2 (b) 2 = (−3.2 N) + (3.8 N) = m/s2 (c) 2 = (3.2 N) + (−3.8 N) = m/s2
Two horizontal forces act on a 2.8 kg chopping block that can slide over a frictionless kitchen counter, which lies in an xy plane. One force is 1 = (3.2 N) + (3.8 N). Find the acceleration of the chopping block in unit-vector notation for each of the following second forces. (a) 2 = (−3.2 N) + (−3.8 N) = m/s2 (b) 2 = (−3.2 N) + (3.8 N) = m/s2 (c) 2 = (3.2 N) + (−3.8 N) = m/s2
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Two horizontal forces act on a 2.8 kg chopping block that can slide over a frictionless kitchen counter, which lies in an xy plane. One force is 1 = (3.2 N) + (3.8 N). Find the acceleration of the chopping block in unit-vector notation for each of the following second forces.
(a) 2 = (−3.2 N) + (−3.8 N)
=
m/s2
(b) 2 = (−3.2 N) + (3.8 N)
=
m/s2
(c) 2 = (3.2 N) + (−3.8 N)
=
m/s2
=
(b) 2 = (−3.2 N) + (3.8 N)
=
(c) 2 = (3.2 N) + (−3.8 N)
=
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