Two horizontal forces act on a 2.7 kg chopping block that can slide over a frictionless kitchen counter, which lies in an xy plane. One force is F₁ = (8.3 N) î+ (1.9 N) 7. Find the acceleration of the chopping block in unit-vector notation when the other force is (a) F₂= (-8.3N) + (-1.9 N). (b) F₂ = (-8.3 N) î+ (1.9N)), and (c) 2 F₂ = (8.3 N) î + ( − 1.9 N) 7. 2

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Chapter1: Units, Trigonometry. And Vectors
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Two horizontal forces act on a 2.7 kg chopping block that can slide over a frictionless kitchen
counter, which lies in an xy plane. One force is F₁ = (8.3 N) î+ (1.9 N) ĵ. Find the acceleration
of the chopping block in unit-vector notation when the other force is (a)
F₂ = ( − 8.3 N) î + ( − 1.9 N) Ĵ, (b) F₂ = ( − 8.3 N) î + (1.9 N) ĵ, and (c)
2
F₂ = (8.3N)i + (-19N) Ĵ.
F2
Transcribed Image Text:Two horizontal forces act on a 2.7 kg chopping block that can slide over a frictionless kitchen counter, which lies in an xy plane. One force is F₁ = (8.3 N) î+ (1.9 N) ĵ. Find the acceleration of the chopping block in unit-vector notation when the other force is (a) F₂ = ( − 8.3 N) î + ( − 1.9 N) Ĵ, (b) F₂ = ( − 8.3 N) î + (1.9 N) ĵ, and (c) 2 F₂ = (8.3N)i + (-19N) Ĵ. F2
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