Four acrobats of mass 67.0 kg, 68.0 kg, 62.0 kg, and 55.0 kg form a human tower, with each acrobat standing on the shoulders of another acrobat. The 67.0-kg acrobat is at the bottom of the tower. (a) What is the normal force acting on the 67.0-kg acrobat? (Enter the magnitude only.) 2469.6 ✔N (b) If the area of each of the 67.0-kg acrobat's shoes is 500 cm², what average pressure (not including atmospheric pressure) does the column of acrobats exert on the floor? 53686.96 X Your response differs from the correct answer by more than 100%. Pa (c) Will the pressure be the same if a different acrobat is on the bottom? Pressure will be the same since the total mass of acrobats remains the same

College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
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### Educational Exercise: Physics of Human Towers

Four acrobats of mass 67.0 kg, 68.0 kg, 62.0 kg, and 55.0 kg form a human tower, with each acrobat standing on the shoulders of another acrobat. The 67.0-kg acrobat is at the bottom of the tower.

#### (a) Question:
What is the normal force acting on the **67.0-kg** acrobat? (Enter the magnitude only.)

**Answer:** 2469.6 N ✔️

---

#### (b) Question:
If the area of each of the 67.0-kg acrobat's shoes is **500 cm²**, what average pressure (not including atmospheric pressure) does the column of acrobats exert on the floor?

**Response:** 53686.96 Pa ❌

*Feedback:* Your response differs from the correct answer by more than 100%.

---

#### (c) Question:
Will the pressure be the same if a different acrobat is on the bottom?

**Answer:** Pressure will be the same since the total mass of acrobats remains the same.

---

This exercise demonstrates concepts of normal force and pressure in the context of a human tower, providing insight into static equilibrium and surface pressure distribution.
Transcribed Image Text:### Educational Exercise: Physics of Human Towers Four acrobats of mass 67.0 kg, 68.0 kg, 62.0 kg, and 55.0 kg form a human tower, with each acrobat standing on the shoulders of another acrobat. The 67.0-kg acrobat is at the bottom of the tower. #### (a) Question: What is the normal force acting on the **67.0-kg** acrobat? (Enter the magnitude only.) **Answer:** 2469.6 N ✔️ --- #### (b) Question: If the area of each of the 67.0-kg acrobat's shoes is **500 cm²**, what average pressure (not including atmospheric pressure) does the column of acrobats exert on the floor? **Response:** 53686.96 Pa ❌ *Feedback:* Your response differs from the correct answer by more than 100%. --- #### (c) Question: Will the pressure be the same if a different acrobat is on the bottom? **Answer:** Pressure will be the same since the total mass of acrobats remains the same. --- This exercise demonstrates concepts of normal force and pressure in the context of a human tower, providing insight into static equilibrium and surface pressure distribution.
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