Two forces of 25 and 45 N act on an object. Their directions differ by 70°. The resulting acceleration has magnitude of 10.0 m/s². What is the mass of the body?
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- When Two forces FA and FB are applied to an object whose mass is 9.15 kg. The larger force is FA. both forces point due east, the object's acceleration has a magnitude of 0.784 m/s². However, when FA points due east and FB points due west, the acceleration is 0.420 m/s², due east. Find (a) the magnitude of FA and (b) the magnitude of FB. (a) Number i (b) Number i Units UnitsThree forces acting on an object are given by F₁ = (-1.951 +5.653) N, F₂ = (4.751 1.351) N, and F3 = (-401) N. The object experiences an acceleration of magnitude 3.90 m/s². (a) What is the direction of the acceleration? (counterclockwise from the +x-axis) (b) What is the mass of the object? kg (c) If the object is initially at rest, what is its speed after 12.0 s? m/s (d) What are the velocity components of the object after 12.0 s? (Let the velocity be denoted by V.) v m/sOnly two forces act on an object (mass = 7.91 kg), as in the drawing. Find the (a) magnitude and (b) direction (relative to the x axis) of the acceleration of the object. +y 60.0 N 40.0 N +x
- Two forces É, = (81.24i – 26.83j) N and É, = (27.41i - 80.52j) N are exerted on a particle. The particle's mass is 23.21 kg. (a) Find the particle's acceleration in component form. (Express your answer in vector form.) a = m/s? (b) What are the magnitude and direction of the acceleration? magnitude |m/s2 direction counterclockwise from the +x axisTwo forces FA and FB are applied to an object whose mass is 7.20 kg. The larger force is FÁ .When both forces point due east, the object's acceleration has a magnitude of 0.453 m/s?. However, when FA points due east and Fg points due west, the acceleration is 0.337 m/s?, due east. Find (a) the magnitude of FA and (b) the magnitude of FB. (a) Number i Units (b) Number i UnitsTwo forces FA and FB are applied to an object whose mass is 10.2 kg. The larger force is FA. When both forces point due east, the object's acceleration has a magnitude of 0.483 m/s². However, when FA points due east and FB points due west, the acceleration is 0.389 m/s², due east. Find (a) the magnitude of FA and (b) the magnitude of FB. (a) Number i (b) Number i eTextbook and Media Save for Later Units Units
- Two forces, F = 2.50 i N and F2 = (1.20 i – 2.30 j) N , act on a 3.00 kg object. Find the magnitude of acceleration of the object. a = 4.0V m/s?If a 3.10 kg body has an acceleration of 7.20 m/s directed at 38.0° to the positive x axis, what is the x component of the net force acting on the body?Two objects are connected by a massless cable passing over a frictionless pulley. Object A is positioned on a table, while object B hangs freely. The coefficient of kinetic friction between object A and the table is 0.09950. If the mass of object A is 150 kg, and the mass of object B is 238 kg, what is the acceleration of the objects?
- An object has a velocity (4.69 m/s)i + (-4.4 m/s)j + (4.73 m/s)k. In a time of 5.5 s its velocity becomes (-2.22 m/s)i + (0.00 m/s)j + (4.73 m/s)k. 1) If the mass of the object is 3.31 kg, what is the magnitude of the net force on the object, in N, during the 5.5 s? Assume the acceleration is constant.Two teams of nine members each engage in a tug of war. Each of the first team's members has an average mass of 72 kg and exerts an average force of 1350 N horizontally. Each of the second team's members has an average mass of 77 kg and exerts an average force of 1373 N horizontally. (a) What is the acceleration (in m/s2 in the direction the heavy team is pulling) of the two teams?A 1.20 kg object is subjected to three forces that give it an acceleration à = (4.80 m/s² )î + (5.00 m/s²). If two of the three forces are F₁ = (28.0 N )i + (11.0 N ) and F₂ = (15.0 N )i + (8.00 N )ĵ, find (a) the x component and (b) the y component of the the third force.