Two forces act on an object of mass M = 5.00 kg as shown in the figure. Because of these forces, the object experiences an acceleration of a = 7.00 m/s² in the positive x-direction. If 01 = 30.0°, calculate the magnitude of F2 given that F = 20.0 N.

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Chapter1: Units, Trigonometry. And Vectors
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Two forces act on an object of mass \( M = 5.00 \, \text{kg} \) as shown in the figure.

Because of these forces, the object experiences an acceleration of \( a = 7.00 \, \text{m/s}^2 \) in the positive x-direction. If \( \theta_1 = 30.0^\circ \), calculate the magnitude of \( \vec{F}_2 \) given that \( F_1 = 20.0 \, \text{N} \).

\[ F_2 = \boxed{\phantom{0000}} \, \text{N} \]

**Diagram Explanation:**

- The diagram shows a set of coordinate axes with the horizontal axis labeled as \( x \) and the vertical axis as \( y \).
- There are two force vectors, \( \vec{F}_1 \) and \( \vec{F}_2 \), acting on the object located at point \( M \).
- \( \vec{F}_1 \) is at an angle \( \theta_1 = 30.0^\circ \) above the positive x-axis.
- \( \vec{F}_2 \) is directed below the positive x-axis, but its angle is unknown, represented as a question mark.
Transcribed Image Text:Two forces act on an object of mass \( M = 5.00 \, \text{kg} \) as shown in the figure. Because of these forces, the object experiences an acceleration of \( a = 7.00 \, \text{m/s}^2 \) in the positive x-direction. If \( \theta_1 = 30.0^\circ \), calculate the magnitude of \( \vec{F}_2 \) given that \( F_1 = 20.0 \, \text{N} \). \[ F_2 = \boxed{\phantom{0000}} \, \text{N} \] **Diagram Explanation:** - The diagram shows a set of coordinate axes with the horizontal axis labeled as \( x \) and the vertical axis as \( y \). - There are two force vectors, \( \vec{F}_1 \) and \( \vec{F}_2 \), acting on the object located at point \( M \). - \( \vec{F}_1 \) is at an angle \( \theta_1 = 30.0^\circ \) above the positive x-axis. - \( \vec{F}_2 \) is directed below the positive x-axis, but its angle is unknown, represented as a question mark.
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