Two forces act on an object of mass M = 5.00 kg as shown in the figure. Because of these forces, the object experiences an acceleration of a = 7.00 m/s² in the positive x-direction. If 01 = 30.0°, calculate the magnitude of F2 given that F = 20.0 N.
Two forces act on an object of mass M = 5.00 kg as shown in the figure. Because of these forces, the object experiences an acceleration of a = 7.00 m/s² in the positive x-direction. If 01 = 30.0°, calculate the magnitude of F2 given that F = 20.0 N.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![Two forces act on an object of mass \( M = 5.00 \, \text{kg} \) as shown in the figure.
Because of these forces, the object experiences an acceleration of \( a = 7.00 \, \text{m/s}^2 \) in the positive x-direction. If \( \theta_1 = 30.0^\circ \), calculate the magnitude of \( \vec{F}_2 \) given that \( F_1 = 20.0 \, \text{N} \).
\[ F_2 = \boxed{\phantom{0000}} \, \text{N} \]
**Diagram Explanation:**
- The diagram shows a set of coordinate axes with the horizontal axis labeled as \( x \) and the vertical axis as \( y \).
- There are two force vectors, \( \vec{F}_1 \) and \( \vec{F}_2 \), acting on the object located at point \( M \).
- \( \vec{F}_1 \) is at an angle \( \theta_1 = 30.0^\circ \) above the positive x-axis.
- \( \vec{F}_2 \) is directed below the positive x-axis, but its angle is unknown, represented as a question mark.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9b84ea90-50cf-43da-a8f9-e0056662f87a%2Fe2c8b084-e9ae-4645-badd-015c7b47fb94%2Fuvgj3wi_processed.png&w=3840&q=75)
Transcribed Image Text:Two forces act on an object of mass \( M = 5.00 \, \text{kg} \) as shown in the figure.
Because of these forces, the object experiences an acceleration of \( a = 7.00 \, \text{m/s}^2 \) in the positive x-direction. If \( \theta_1 = 30.0^\circ \), calculate the magnitude of \( \vec{F}_2 \) given that \( F_1 = 20.0 \, \text{N} \).
\[ F_2 = \boxed{\phantom{0000}} \, \text{N} \]
**Diagram Explanation:**
- The diagram shows a set of coordinate axes with the horizontal axis labeled as \( x \) and the vertical axis as \( y \).
- There are two force vectors, \( \vec{F}_1 \) and \( \vec{F}_2 \), acting on the object located at point \( M \).
- \( \vec{F}_1 \) is at an angle \( \theta_1 = 30.0^\circ \) above the positive x-axis.
- \( \vec{F}_2 \) is directed below the positive x-axis, but its angle is unknown, represented as a question mark.
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