Two forces act on an object of mass \( M = 5.00 \, \text{kg} \) as shown in the figure.Because of these forces, the object experiences an acceleration of \( a = 7.00 \, \text{m/s}^2 \) in the positive x-direction. If \( \theta_1 = 30.0^\circ \), calculate the magnitude of \( \vec{F}_2 \) given that \( F_1 = 20.0 \, \text{N} \).\[ F_2 = \boxed{\phantom{0000}} \, \text{N} \]**Diagram Explanation:**- The diagram shows a set of coordinate axes with the horizontal axis labeled as \( x \) and the vertical axis as \( y \).- There are two force vectors, \( \vec{F}_1 \) and \( \vec{F}_2 \), acting on the object located at point \( M \).- \( \vec{F}_1 \) is at an angle \( \theta_1 = 30.0^\circ \) above the positive x-axis.- \( \vec{F}_2 \) is directed below the positive x-axis, but its angle is unknown, represented as a question mark.

mass = M = 5 Kg acceleration = a = 7 m/s2 ( +x- direction ) F1= 20 N F2= ?

Two forces act on an object of mass M = 5.00 kg as shown in the figure. Because of these forces, the object experiences an acceleration of a = 7.00 m/s² in the positive x-direction. If 01 = 30.0°, calculate the magnitude of F2 given that F = 20.0 N.

Two forces act on an object of mass M = 5.00 kg as shown in the figure. Because of these forces, the object experiences an acceleration of a = 7.00 m/s² in the positive x-direction. If 01 = 30.0°, calculate the magnitude of F2 given that F = 20.0 N.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

Two forces act on an object of mass \( M = 5.00 \, \text{kg} \) as shown in the figure.

Because of these forces, the object experiences an acceleration of \( a = 7.00 \, \text{m/s}^2 \) in the positive x-direction. If \( \theta_1 = 30.0^\circ \), calculate the magnitude of \( \vec{F}_2 \) given that \( F_1 = 20.0 \, \text{N} \).

\[ F_2 = \boxed{\phantom{0000}} \, \text{N} \]

**Diagram Explanation:**

- The diagram shows a set of coordinate axes with the horizontal axis labeled as \( x \) and the vertical axis as \( y \).
- There are two force vectors, \( \vec{F}_1 \) and \( \vec{F}_2 \), acting on the object located at point \( M \).
- \( \vec{F}_1 \) is at an angle \( \theta_1 = 30.0^\circ \) above the positive x-axis.
- \( \vec{F}_2 \) is directed below the positive x-axis, but its angle is unknown, represented as a question mark.

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