two experiments were conducted, both have mean= 18, n=18, s=1. P(Xa-Xb>1) solve using f distribution
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two experiments were conducted, both have
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- A normal distribution has a mean of μ= 54 and a standard deviation of σ=6 What is the probability of selecting a sample of n = 4 scores with a mean more than M = 51?I have tried multiple ways to solve this but I am just not getting it! Any assisstance I will greatly appreciate.Assume a normally distributed population with a mean = 90 and standarddeviation = 12. Be sure to sketch the curves, include formulas & round appropriately. If you select one person at random from this population (M = 90, SD = 12)and find his/her score on this variable to be 68 would you be surprised/consider this score extreme (yes/no)? Why/why not? Be sure to show your work when justifying the answer.
- A sample obtained from a population with σ = 12 has a standard error of σx̅ = 2 points. How many scores are in the sample?11% of all Americans suffer from sleep apnea. A researcher suspects that a different percentage of those who live in the inner city have sleep apnea. Of the 344 people from the inner city surveyed, 34 of them suffered from sleep apnea. What can be concluded at the level of significance of αα = 0.01? The test statistic= (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.)X is a normally distributed variable with mean = 60 and standard deviation = 10 %3D For a randomly selected score from this distribution what is the probability that X is less than 42
- A previous study showed to determine whether a sales tax on soda will reduce consumption of soda in the US below the current per-capita level of about 50 gallons of soda per year. Hypotheses Test is Ho: m(mue) =50 vs. Ha: m<50 where m (mue) represents the average annual consumption of soda in communities where the sales tax is implemented. (b) Now supposed sample results give a p-value of 0.41. Interpret this p-value in terms of random chance and in the context of taxes and soda consumption.Use the information given in the table below to find a 95% Prediction Interval for y when x = 10. n = 20 x_bar = 15 %3D beta0_hat = 53 SSXX = 62 beta1_hat = - 4.5 S = 9 (- 14.79, 30.79) (-0.57, 16.57) (-10.25, 26.25) O (- 4.73, 20.73)The processing time for the robogate has a normal distribution with mean 23 sec and standard deviation 2sec. Find the probability that the next operation of the robogate will take 27.4 sec or less. The probability is.
