Part F - Example: Finding Two Forces (Part I)Two dimensional dynamics often involves solving for two unknown quantities in twoseparate equations describing the total force. The block in (Figure 1) has a massm = 10 kg and is being pulled by a force F on a table with coefficient of staticfriction μ = 0.3. Four forces act on it:• The applied force F (directed 0 = 30° above the horizontal).• The force of gravity F = mg (directly down, where g = 9.8 m/s²).• The normal force N (directly up).• The force of static friction f (directly left, opposing any potentialmotion).If we want to find the size of the force necessary to just barely overcome staticfriction (in which case fs = μg N), we use the condition that the sum of the forcesin both directions must be 0. Using some basic trigonometry, we can write thiscondition out for the forces in both the horizontal and vertical directions,respectively, as:• F cos 0 - μg N=0• Fsin 0+N-mg=0In order to find the magnitude of force F, we have to solve a system of twoequations with both F and the normal force N unknown. Use the methods wehave learned to find an expression for F in terms of m, g, 0, and μg (no N).Express your answer in terms of m, g, 0, and μg.

Name: Part F - Example: Finding Two Forces (Part I)Two dimensional dynamics
Uploaded: 2024-03-20T06:56:46.000Z
Channel: Bartleby
Description: Part F - Example: Finding Two Forces (Part I)Two dimensional dynamics often involves solving for two unknown quantities in twoseparate equations describing the total force. The block in (Figure 1) has a massm = 10 kg and is being pulled by a force F