Two different types of injection-molding machines are used to form plastic parts. A part is considered defective if it has excessive shrinkage or is discolored. Two random samples, each of size 300, are selected, and 15 defective parts are found in the sample from machine 1, while 8 defective parts are found in the sample from machine 2. Suppose that p1 - 0.05 and p2 = 0.01. (a) With the sample sizes given, what is the power of the test for this two sided alternative? Power i 786 Round your answer to three decimal places (e.g. 98.765).

Q: dx 0 4-x

A: To evaluate the integration.

Q: 36 43 10-

A: The quartile deviation is computed by using the table below. The class boundaries are computed by…

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A: Solution is done in step 2

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A: In a parallelogram diagonals bisect each other.

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A: Given that the integral ∫36∫47xy dydx. Find the value of given integral.

Q: 7. Use your graph to estimate how the scale factor changes between a box with volume of 1 cubic foot…

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Q: 3) %3D 2.

A: Two dimensional wave equation , by using separation of method

Q: 4. w/- 4. 2.

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A: Introduction: The division is one of the four basic mathematical operations, alongside addition,…

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A: Given; 1. [(K2+7k+10).(k2+3k)]/[(k2+8k+15)(k2-4k-12)] 2. 7/(x-2) - 5/(2-x).

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Q: (c) Give an orthonormal basis for Span {x₁, X2, X3}.

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Q: 4 y = -x-8 8. (14,-16)

A: Given equation is y = (4/7)x - 8

Q: (b) Give an orthogonal basis for Span {X₁, X₂, X3}.

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Q: Simplify. 7/16-V54

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Q: For the following equation, determine the values of the missing entries. Reduce all fractions to…

A: given x=y2 complete the table as follows

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A: Given:   x y 644 623 493 472 532 492 462 661 565 540   502   549   518

Q: +1 dx -8 Evaluate

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A: Explanation and solution is given below....

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A: ∑n=11009i-2n=∑n=11009-1-n          =∑n=11008-1-n+-1-1009          =-1+1-1+1...+1+-1-1009…

Q: 4. 15 33,

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A: We Solve the Equation, Find The value of x.  Given Equation is 5x+8= 78.

Q: 248.96/3.20

A: we want to solve out the following 248.96/3.20let N = 248.96/3.20

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A: The integral is: ∫x1x2dsx. To Do: We have to evaluate this integral.

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