Two constant forces act on an object of mass m = 5.50 kg object moving in the xy plane as shown in the figure below. Force F, is 23.0 N at 35.0°, and force F2 is 40.0 N at 150°. At time t = 0, the object is at the origin and has velocity (4.501 + 2.605) m/s. 150° F. (a) Express the two forces in unit-vector notation. F₁ = N N (b) Find the total force exerted on the object. 35.0° N (c) Find the object's acceleration. m/s² m/s Now, consider the instant t = 3.00 s. (d) Find the object's velocity. (e) Find Its position. m O ASK YOUR TEACHER PRACTICE ANOTHER
Two constant forces act on an object of mass m = 5.50 kg object moving in the xy plane as shown in the figure below. Force F, is 23.0 N at 35.0°, and force F2 is 40.0 N at 150°. At time t = 0, the object is at the origin and has velocity (4.501 + 2.605) m/s. 150° F. (a) Express the two forces in unit-vector notation. F₁ = N N (b) Find the total force exerted on the object. 35.0° N (c) Find the object's acceleration. m/s² m/s Now, consider the instant t = 3.00 s. (d) Find the object's velocity. (e) Find Its position. m O ASK YOUR TEACHER PRACTICE ANOTHER
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Transcribed Image Text:ASK YOUR TEACHER
Two constant forces act on an object of mass m = 5.50 kg object moving in the xy plane as shown in the figure below. Force F, is 23.0 N at 35.0°, and force F2 is 40.0 N at 150°. At time t = 0, the
object is at the origin and has velocity (4.501 + 2.605) m/s.
150°
F.
(a) Express the two forces in unit-vector notation.
F₁ =
N
N
(b) Find the total force exerted on the object.
35.0⁰
N
(c) Find the object's acceleration.
m/s²
m/s
Now, consider the instant t = 3.00 s.
(d) Find the object's velocity.
(e) Find Its position.
m
(
PRACTICE ANOTHER
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