Two conductors having net charges of +20.0 µC and -20.0 µC have a potential difference of 20.0 V between them. (a) Determine the capacitance of the system. F (b) What is the potential difference between the two conductors if the charges on each are increased to +400.0 µC and -400.0 µC? V
Two conductors having net charges of +20.0 µC and -20.0 µC have a potential difference of 20.0 V between them. (a) Determine the capacitance of the system. F (b) What is the potential difference between the two conductors if the charges on each are increased to +400.0 µC and -400.0 µC? V
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Problem Statement:**
Two conductors having net charges of +20.0 μC and -20.0 μC have a potential difference of 20.0 V between them.
**Questions:**
(a) Determine the capacitance of the system.
- [ ] F
(b) What is the potential difference between the two conductors if the charges on each are increased to +400.0 μC and -400.0 μC?
- [ ] V
**Explanation:**
In this problem, you are dealing with a capacitor system. The capacitance (C) can be determined using the formula:
\[ C = \frac{Q}{V} \]
where \( Q \) is the charge and \( V \) is the potential difference.
1. For part (a), you will need to calculate the capacitance using the initial charges and potential difference provided.
2. For part (b), use the newly provided charges to determine the new potential difference, using the same capacitance calculated in part (a).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff26bd2c7-a69a-414f-95bc-e32ed97937d0%2F88ff7665-8fe5-4d04-b69e-cabf081d1bd0%2Fnb0cmjn_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
Two conductors having net charges of +20.0 μC and -20.0 μC have a potential difference of 20.0 V between them.
**Questions:**
(a) Determine the capacitance of the system.
- [ ] F
(b) What is the potential difference between the two conductors if the charges on each are increased to +400.0 μC and -400.0 μC?
- [ ] V
**Explanation:**
In this problem, you are dealing with a capacitor system. The capacitance (C) can be determined using the formula:
\[ C = \frac{Q}{V} \]
where \( Q \) is the charge and \( V \) is the potential difference.
1. For part (a), you will need to calculate the capacitance using the initial charges and potential difference provided.
2. For part (b), use the newly provided charges to determine the new potential difference, using the same capacitance calculated in part (a).
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