Two circular holes, one larger than the other, are cut in the side of a large water tank whose top is open to the atmosphere. Hole 1 isthe larger hole, and hole 2 is the smaller hole. The center of one of these holes is located 3 times as far beneath the surface of the wateras the other. The volume flow rate of the water coming out of the holes is the same. (a) Decide which hole (1 or 2) is located nearest thesurface of the water. (b) Calculate the ratio of the radius of the larger hole to the radius of the smaller hole, r/rg.Water level(a) Number(b) Number iUnitsUnits

Name: Two circular holes, one larger than the other, are cut in the side of
Uploaded: 2024-03-20T06:51:10.000Z
Channel: Bartleby
Description: Two circular holes, one larger than the other, are cut in the side of a large water tank whose top is open to the atmosphere. Hole 1 isthe larger hole, and hole 2 is the smaller hole. The center of one of these holes is located 3 times as far beneat

The expression for the volume flow rate,In this case, the center of one of these holes is located twice as far beneath the surface of the water as the other. Also, the volume flow rate of the water coming out of the holes in the same.The upper hole should have a larger area because the volume flow rate is the same at each point. So, the speed of the water flow is greater at a lower point.Therefore, the upper hole is located nearest to the surface of the water.In this case, the pressureUsing Bernoulli’s equation,The speeds of the water flow,The ratio of the speeds,The water flow rate,So, the ratio of the radiusLarge hole should have at upper locationRatio of radius is 1.32