Two charges are placed between the plates of a parallel plate capacitor. One charge is +91 and the other is q2 = +7.33 μC. The charge per unit area on each plate has a magnitude of a = 9.75 x 106 C/m². The force on q1 due to q2 equals the force on q1 due to the electric field of the parallel plate capacitor. What is the distance r between the two charges? Hait
Two charges are placed between the plates of a parallel plate capacitor. One charge is +91 and the other is q2 = +7.33 μC. The charge per unit area on each plate has a magnitude of a = 9.75 x 106 C/m². The force on q1 due to q2 equals the force on q1 due to the electric field of the parallel plate capacitor. What is the distance r between the two charges? Hait
College Physics
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Two charges are placed between the plates of a parallel plate capacitor. One charge is +91 and the other is q2 = +7.33 μC. The charge
per unit area on each plate has a magnitude of a = 9.75 x 10-6 C/m². The force on 91 due to q2 equals the force on q1 due to the electric
field of the parallel plate capacitor. What is the distance r between the two charges?
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Expert Solution

Step 1: Determine the given variables
Charge, q2 = 7.33 μC
Charge density, σ = 9.75×10-6 C/m²
Distance, r = ?
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