Two cars, both of mass m, collide and stick together. Prior to the collision, one car had been traveling north at speed 2v, while the second was traveling at speed v at an angle south of east (as indicated in the figure). After the collision, the two-car system travels at speed ufinal at an angle east of north. (Figure 1) Figure 2v < 1 of 1 > Vfinal ▼ Part A If the speed u was 5.1 m/s and the angle was 21.5 degrees, find the speed Ufinal of the joined cars after the collision. ►View Available Hint(s) 15. ΑΣΦΑ Ufinal= Submit Part B 0= What is the angle with respect to north made by the velocity vector of the two cars after the collision? ▸ View Available Hint(s) Submit 17 ΑΣΦ 5 BATE ? ? m/s degrees
Two cars, both of mass m, collide and stick together. Prior to the collision, one car had been traveling north at speed 2v, while the second was traveling at speed v at an angle south of east (as indicated in the figure). After the collision, the two-car system travels at speed ufinal at an angle east of north. (Figure 1) Figure 2v < 1 of 1 > Vfinal ▼ Part A If the speed u was 5.1 m/s and the angle was 21.5 degrees, find the speed Ufinal of the joined cars after the collision. ►View Available Hint(s) 15. ΑΣΦΑ Ufinal= Submit Part B 0= What is the angle with respect to north made by the velocity vector of the two cars after the collision? ▸ View Available Hint(s) Submit 17 ΑΣΦ 5 BATE ? ? m/s degrees
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![**Collision Analysis:**
**Problem Statement:**
Two cars, each with mass \( m \), collide and stick together. Before the collision:
- One car travels north at speed \( 2v \).
- The other car travels at speed \( v \) at an angle \( \phi \) south of east.
After the collision, the combined cars travel at speed \( v_{\text{final}} \) at an angle \( \theta \) east of north.
**Figure Explanation:**
- The figure illustrates the motion of two cars before and after collision.
- The blue car moves directly north with velocity \( 2v \).
- The yellow car moves with velocity \( v \) at an angle \( \phi \) south of east.
- After the collision, the resulting velocity \( v_{\text{final}} \) is shown at an angle \( \theta \) east of north.
**Part A:**
Determine \( v_{\text{final}} \) after the collision, given \( v = 5.1 \, \text{m/s} \) and \( \phi = 21.5^\circ \).
\[ v_{\text{final}} = \, \_\_\_ \, \text{m/s} \]
**Part B:**
Find the angle \( \theta \) with respect to north made by the velocity vector after the collision.
\[ \theta = \, \_\_\_ \, \text{degrees} \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffb2133c9-e1e5-4d56-9c72-044227328930%2F920eeabc-4a15-4d92-8c9e-cfd3c77df4cd%2Fj55y5sg_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Collision Analysis:**
**Problem Statement:**
Two cars, each with mass \( m \), collide and stick together. Before the collision:
- One car travels north at speed \( 2v \).
- The other car travels at speed \( v \) at an angle \( \phi \) south of east.
After the collision, the combined cars travel at speed \( v_{\text{final}} \) at an angle \( \theta \) east of north.
**Figure Explanation:**
- The figure illustrates the motion of two cars before and after collision.
- The blue car moves directly north with velocity \( 2v \).
- The yellow car moves with velocity \( v \) at an angle \( \phi \) south of east.
- After the collision, the resulting velocity \( v_{\text{final}} \) is shown at an angle \( \theta \) east of north.
**Part A:**
Determine \( v_{\text{final}} \) after the collision, given \( v = 5.1 \, \text{m/s} \) and \( \phi = 21.5^\circ \).
\[ v_{\text{final}} = \, \_\_\_ \, \text{m/s} \]
**Part B:**
Find the angle \( \theta \) with respect to north made by the velocity vector after the collision.
\[ \theta = \, \_\_\_ \, \text{degrees} \]
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