puck mass stationary puck. After the collision, one puck moves off at an angle ₁ with a speed of ₁, and the other puck moves off at an angle ₂ with a speed of V₂. a) What are the speeds ₁ and ₂ if ₁ + ₂ = 90°? Express your answers in terms V₁ and ₁. b) Is the collision inelastic or (totally) elastic? Support your answer with a calculation.
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- Please help me understand the concept of this practice problem and how to work these types out. Thanks() THE FOLLOWING QUESTIONS ARE BASED ON THE INFORMATION GIVEN BELOW. Block m, of mass 15 kg moving with velocity v = 33 m/s on a frictionless plane collides block mg which is connected to block m3 by a long. massless spring with spring constant k = 7000 N/m: see the figure. Each of blocks mą and mg has a mass of 5 kg. Before the collision, blocks mą and mg are stationary and the spring is relaxed. m2 Frictionless - For parts A. B and Cassume that the collision of blocks m, and ma is completely inelastic. (Because the spring is relaxed before the collision. block mạ does not move at the instant of impact therefore (m, +m2) must move through a finite displacement before any force acts on mg and cause it to move) • For parts D and Eassume that the collision of blocks m, and m, is elastic. (Because the spring is relaxed before the collision. block my does not move at the instant of impact therefore mạ must move through a finite displacement before any force acts on mg and cause it to move)…two shuffleboard disks of equal mass, one orange, and the other green are involved in an elastic glancing collision. the green disk is initially at rest and is struck by the orange disk moving initially to the right at voi=5.95 m/s as in figure a, after the collision, the orange disk moves in a direction that make an angle of theatre =34.0 degrees with the horizontal axis makes an angle =56.0 degrees. determine the speed of each disk after the collision.
- Why is the selected answer wrong? What is the correct answer?A 1500kg sport car is moving westbound at 20m/s on a level road when it collided with a 4000kg truck driving east on the same road at 15m/s. The two vehicles remain locked together after the collision. a)what are is the magnitude of the velocity of the two vehicles just after the collision?After the ball A hits (or collides with) the ball B, they are both observed to move off at 45° to the x axis,ball A above the x axis and ball B below. So ?′A= 45° and ?′B = −45°.Is the collision elastic? Justify your answer
- microblology textb. PHY166_onlıne Jab. Pinterest Word sdev E Reading li Constants An atomic nucleus at rest decays radioactively into an alpha particle and a different nucleus. Part A What will be the speed of this recoiling nucleus if the speed of the alpha particle is 2.2x105 m/s ? Assume the recoiling nucleus has a mass 57 times greater than that of the alpha particle. Express your answer to two significant figures and include the appropriate units. HÁ Vnucleus = Value Units Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining Provide Feedback Next > P Pearson Copyright © 2021 Pearson Education Inc. All rights reserved. I Terms of Use | Privacy Policy | Permisstons | Contact Us | V0 3:44 acerAsteroid X, speeding at 100 m/s towards an equally massive but stationary asteroid Y, collides with a glancing blow. After collision, X is deflected 350 from its original direction while Y travels at 450 to the original direction of X. See the before & after picture of the collision below. Assuming total momentum is conserved, find the speed of each asteroid after collision. a.) V = 58.2 m/s, v = 71.8 m/s b.) v = 58.2 m/s, V = 71.8 m/sA two dimensional collision between a green and a purple ball, where the purple ball strikes the green. If the data for both objects' velocities (x and y components) versus time are provided, and the mass of the balls are identical, what is a way to determine if the momentum of the system conserved? Explain your methodology. Green ball: vx = 0 m/s from t = 0 s to t = 0.4 s vx = 17.42 m/s from t = 0.5 s to t = 5 s vy = 0 m/s from t = 0 s to t = 0.4 s vy = -8.01 m/s from t = 0.5 s to t = 5 s Purple ball: vx = 22.3 m/s from t = 0 s to t = 0.4 s vx = 4.878 m/s from t = 0.5 s to t = 5 s vy = 2.6 m/s from t = 0 s to t = 0.4 s vy = 10.61 m/s from t = 0.5 s to t = 5 s
- On a frictionless horizontal air table, puck A (with mass 0.255 kgkg ) is moving toward puck B (with mass 0.367 kgkg ), which is initially at rest. After the collision, puck A has velocity 0.121 m/sm/s to the left, and puck B has velocity 0.655 m/sm/s to the right. What was the speed vAivAiv_Ai of puck A before the collision? Calculate ΔKΔKDeltaK, the change in the total kinetic energy of the system that occurs during the collision.(ODC-1) Consider two hockey pucks, each with mass 1.25 kg, on frictionless ice. Puck A is initially moving due east at 2.35 m/s towards puck B, which is initially stationary. The pucks. collide head on. After the collision, puck B moves east with a speed of 1.45 m/s. (a) What is puck A's speed (in m/s) after collision? What direction is it moving in? (b) How much kinetic energy (in Joules) is lost from the system during the collision? (c) If the collision were completely elastic, what wold the final speed and direction of each puck be? (CM-1) Calculate the (x v) position of the center of mass of the 4 particles shown below