Two cards are drawn at random from a pack without replacement. What is the probability that the first is an Ace but the second is not an Ace? The answer is 16/221, but how can this me done the standard way: P(A) = |A| / |S| With |S| = 52 choose 2

College Algebra
10th Edition
ISBN:9781337282291
Author:Ron Larson
Publisher:Ron Larson
Chapter8: Sequences, Series,and Probability
Section8.7: Probability
Problem 4ECP: Show that the probability of drawing a club at random from a standard deck of 52 playing cards is...
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Two cards are drawn at random from a pack without replacement. What is the probability that the first is an Ace but the second is not an Ace? The answer is 16/221, but how can this me done the standard way: P(A) = |A| / |S| With |S| = 52 choose 2
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