From a group of 10 children, a team of 5 (red team) is randomly chosen. The remaining 5 children are on blue team. Two of the children are best friends, what is the probability they will end up on the same team?  Can u show me the work for this?

A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
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Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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From a group of 10 children, a team of 5 (red team) is randomly chosen. The remaining 5 children are on blue team. Two of the children are best friends, what is the probability they will end up on the same team? 

Can u show me the work for this?

Expert Solution
Step 1

There are total 10 children. We can select the red team in 10C5=252 ways

When the red team is selected then there will be (10-5)=5 children left.

We can select the blue team in 5C5=1 way.

So total number of ways to form two teams= 252×1=252.

 

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