Two blocks each of mass m = 3.54 kg are fastened to the top of an elevator as in the figure. T₁ m T₂ m (a) If the elevator has an upward acceleration a = 1.60 m/s², find the tensions T₁ and T₂ in the upper and lower strings. T₁ = N N T₂ = (b) If the strings can withstand a maximum tension of 95.0 N, what maximum acceleration can the elevator have before the upper string breaks? m/s²

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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Two blocks each of mass \( m = 3.54 \, \text{kg} \) are fastened to the top of an elevator as in the figure.

![Elevator Diagram](image)
- The diagram depicts two blocks, each with mass \( m \), connected by strings inside an elevator. The elevator is accelerating upward with acceleration \( \vec{a} \).
- The upper string has tension \( T_1 \) and the lower string has tension \( T_2 \). Arrows indicate the direction of acceleration and forces on the blocks.

**Question (a):**
If the elevator has an upward acceleration \( a = 1.60 \, \text{m/s}^2 \), find the tensions \( T_1 \) and \( T_2 \) in the upper and lower strings.

- \( T_1 = \) ___ N
- \( T_2 = \) ___ N

**Question (b):**
If the strings can withstand a maximum tension of \( 95.0 \, \text{N} \), what maximum acceleration can the elevator have before the upper string breaks?

- ___ \(\text{m/s}^2\)
Transcribed Image Text:Two blocks each of mass \( m = 3.54 \, \text{kg} \) are fastened to the top of an elevator as in the figure. ![Elevator Diagram](image) - The diagram depicts two blocks, each with mass \( m \), connected by strings inside an elevator. The elevator is accelerating upward with acceleration \( \vec{a} \). - The upper string has tension \( T_1 \) and the lower string has tension \( T_2 \). Arrows indicate the direction of acceleration and forces on the blocks. **Question (a):** If the elevator has an upward acceleration \( a = 1.60 \, \text{m/s}^2 \), find the tensions \( T_1 \) and \( T_2 \) in the upper and lower strings. - \( T_1 = \) ___ N - \( T_2 = \) ___ N **Question (b):** If the strings can withstand a maximum tension of \( 95.0 \, \text{N} \), what maximum acceleration can the elevator have before the upper string breaks? - ___ \(\text{m/s}^2\)
Expert Solution
Step 1

a)

Determine the tension T2.

T2=ma+mgT2=(3.54 kg)(1.60 m/s2)+(3.54 kg)(9.8 m/s2)T2=40.356 N

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