Two blocks are free to slide along the frictionless wooden track as shown in the figure. The block of mass m1 = 5 kg is released from rest from the position shown, at height h = 5.00 meters above the flat part of the track. At the bottom of the track rests mass m2 = 10 kg.
Two blocks are free to slide along the frictionless wooden track as shown in the figure. The block of mass m1 = 5 kg is released from rest from the position shown, at height h = 5.00 meters above the flat part of the track. At the bottom of the track rests mass m2 = 10 kg.
No work is done by non-conservative forces
a.What is the speed of block m1 just as it reaches but before it collides with block m2 (use Cons. Of Energy)?
b.What is the velocity of m1 just after it collides elastically with m2 (use Conservation of Momentum)?
and what is the velocity of m2 just after it collides elastically with m1 (use Conservation of Momentum)?
c. How far back up the ramp does m1 rise after the collision (use Cons. Of Energy?) and also find that if an 7 kg block, m3, that lies to the right of m2, is moving toward m2 (after m2’s collision with m1) at a speed of 26.8 mph (conversion!), what is the velocity of the m2/m3 couple after they collide in a perfectly inelastic collision (sticking together)… (recall 1 in = 2.54 cm, 1 mi = 5280 ft, 1 ft = 12 in)?
Please solve all the parts.
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