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Two blocks are connected by a massless rope as shown below. The mass of the block on the table is m, and the hanging mass is m₂. The table and the pulley are frictionless. m₁ m₂ Subpart 1: Draw FBDs In your notebook, draw free body diagrams for m, and m₂ using the template as shown below. The forces acting on the system are weights of the blocks, m₁g, and m₂g, the tension in the string T and the normal reaction N, of the table on m₁. L m₁ m. (1) Newton's Second Law for m, in terms of weights of the blocks, m,g, and m₂g, the tension in the string T and the normal reaction N₁ of the table on m, can be written as (use the coordinate axes for signs of different forces): ΣF₂= ΣF= m₁a₁x =m₁a₁.y (ii) Newton's Second Law for m₂ in terms of weights of the blocks, m₁g, and m₂g, the tension in the string T and the normal reaction N₁ of the table on m, can be written as: Note: The motion of m₂ is along the y-direction only. ΣF= m₂a2.y (iii) How are a, and a related? What are the directions of a, and a₂? Magnitudes of a, and a₂. A. a, is greater than a₂ B. a, is less than a₂ C. a, is equal to a₂ Directions of a, and a₂ A. a, is to the right and a2 is up ai B. is to the right and a2 is down C. a, is to the left and a2 is up D. a, is to the left and a₂ is down

Two blocks are connected by a massless rope as shown below. The mass of the block on the table is m, and the hanging mass is m₂. The table and the pulley are frictionless. m₁ m₂ Subpart 1: Draw FBDs In your notebook, draw free body diagrams for m, and m₂ using the template as shown below. The forces acting on the system are weights of the blocks, m₁g, and m₂g, the tension in the string T and the normal reaction N, of the table on m₁. L m₁ m. (1) Newton's Second Law for m, in terms of weights of the blocks, m,g, and m₂g, the tension in the string T and the normal reaction N₁ of the table on m, can be written as (use the coordinate axes for signs of different forces): ΣF₂= ΣF= m₁a₁x =m₁a₁.y (ii) Newton's Second Law for m₂ in terms of weights of the blocks, m₁g, and m₂g, the tension in the string T and the normal reaction N₁ of the table on m, can be written as: Note: The motion of m₂ is along the y-direction only. ΣF= m₂a2.y (iii) How are a, and a related? What are the directions of a, and a₂? Magnitudes of a, and a₂. A. a, is greater than a₂ B. a, is less than a₂ C. a, is equal to a₂ Directions of a, and a₂ A. a, is to the right and a2 is up ai B. is to the right and a2 is down C. a, is to the left and a2 is up D. a, is to the left and a₂ is down

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Subpart 3: SOLVE FOR ACCELERATION & TENSION SYMBOLICALLY Use the results of Subpart 2 and mathematical manipulations to answer the following. (i) Solve for the acceleration of the blocks in terms of m₁, m₂, & g, ✓ (ii) Solve for tension in the strings in terms of m₁, m₂, & g. T= a = Cross-Check: If m₁ is zero, what should the acceration of m₂ be? Does your answer support that? Subpart 4: CALCULATE NUMERICAL VALUES The mass of the block on the table is 4 kg and the hanging mass is 1.2 kg. Assume all quantities are correct to 2 significant figures. (i) Calculate the magnitude of the acceleration of m₂. Enter to 2 significant figures a = (ii) Calculate the tension force in the string. Enter to 2 significant figures T= ✔N m s² (iii) Find the speed with which the hanging mass hits the floor if it starts from rest and is initially located 1.4 m from the floor. V= ✓ m S
Transcribed Image Text:Subpart 3: SOLVE FOR ACCELERATION & TENSION SYMBOLICALLY Use the results of Subpart 2 and mathematical manipulations to answer the following. (i) Solve for the acceleration of the blocks in terms of m₁, m₂, & g, ✓ (ii) Solve for tension in the strings in terms of m₁, m₂, & g. T= a = Cross-Check: If m₁ is zero, what should the acceration of m₂ be? Does your answer support that? Subpart 4: CALCULATE NUMERICAL VALUES The mass of the block on the table is 4 kg and the hanging mass is 1.2 kg. Assume all quantities are correct to 2 significant figures. (i) Calculate the magnitude of the acceleration of m₂. Enter to 2 significant figures a = (ii) Calculate the tension force in the string. Enter to 2 significant figures T= ✔N m s² (iii) Find the speed with which the hanging mass hits the floor if it starts from rest and is initially located 1.4 m from the floor. V= ✓ m S
1. Two blocks are connected by a massless rope as shown below. The mass of the block on the table is m₁ and the hanging mass is m₂. The table and the pulley are frictionless. y m₁ X a₁ Subpart 1: Draw FBDs In your notebook, draw free body diagrams for m, and m₂ using the template as shown below. The forces acting on the system are weights of the blocks, m₁g, and m₂g, the tension in the string T and the normal reaction N₁ of the table on m₁. 1 m m₂ ā₂ m2 (i) Newton's Second Law for m, in terms of weights of the blocks, m₁g, and måg, the tension in the string T and the normal reaction N₁ of the table on m, can be written as (use the coordinate axes for signs of different forces): 1 ΣF= ΣF₂= ✓=m₁a₁₁x ✔=m₁a₁₁y (ii) Newton's Second Law for m₂ in terms of weights of the blocks, måg, and måg, the tension in the string T and the normal reaction N₁ of the table on m, can be written as: Note: The motion of m₂ is along the y-direction only. ΣF₁ = ✓ = m₂a2,y (iii) How are a, and a related? What are the directions of a, and a₂? Magnitudes of a₁ and a2. A. a, is greater than a B. a, is less than a₂ C. a, is equal to a2 C. Directions of a₁ and a2 A. a, is to the right and a2 is up B. a₁ is to the right and a₂ is down a₁ is to the left and a2 is up D. a, is to the left and an is down
Transcribed Image Text:1. Two blocks are connected by a massless rope as shown below. The mass of the block on the table is m₁ and the hanging mass is m₂. The table and the pulley are frictionless. y m₁ X a₁ Subpart 1: Draw FBDs In your notebook, draw free body diagrams for m, and m₂ using the template as shown below. The forces acting on the system are weights of the blocks, m₁g, and m₂g, the tension in the string T and the normal reaction N₁ of the table on m₁. 1 m m₂ ā₂ m2 (i) Newton's Second Law for m, in terms of weights of the blocks, m₁g, and måg, the tension in the string T and the normal reaction N₁ of the table on m, can be written as (use the coordinate axes for signs of different forces): 1 ΣF= ΣF₂= ✓=m₁a₁₁x ✔=m₁a₁₁y (ii) Newton's Second Law for m₂ in terms of weights of the blocks, måg, and måg, the tension in the string T and the normal reaction N₁ of the table on m, can be written as: Note: The motion of m₂ is along the y-direction only. ΣF₁ = ✓ = m₂a2,y (iii) How are a, and a related? What are the directions of a, and a₂? Magnitudes of a₁ and a2. A. a, is greater than a B. a, is less than a₂ C. a, is equal to a2 C. Directions of a₁ and a2 A. a, is to the right and a2 is up B. a₁ is to the right and a₂ is down a₁ is to the left and a2 is up D. a, is to the left and an is down
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