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A golfer is trying to hit their ball over a 28 m tree. The ball leaves their club at an angle of 23° above the horizon. What is the minimum speed the golf ball would need to have after being hit by the club to make it over the tree?

A golfer is trying to hit their ball over a 28 m tree. The ball leaves their club at an angle of 23° above the horizon. What is the minimum speed the golf ball would need to have after being hit by the club to make it over the tree?

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A golfer is trying to hit their ball over a 28 m tree. The ball leaves their club at an angle of 23° above the horizon. What is the minimum speed the golf ball would need to have after being hit by the club to make it over the tree?
Transcribed Image Text:A golfer is trying to hit their ball over a 28 m tree. The ball leaves their club at an angle of 23° above the horizon. What is the minimum speed the golf ball would need to have after being hit by the club to make it over the tree?
Given data. - h = height of the tree = 28 m 8 = angle of projection of ball = 23° Required - V = minimum speed the ball would need to - have hit by the club to make it over the tree We will find the answer using formula sin = sin(23⁰) = 0.3907 Sin = 0.3907 Let Vy C minimum value of Velocity = (2gxh) 1/2) the standard component of Vy = (2gxh) 1/² Vy = (2x 9,81 m/s² x 28m) 1/2 vy = 23.438 m/s =23,438m/s Let V = minimum speed of the ball would need to have hit by the club to make it over the tree V= 1 = Vy / sine = 23.438 m/s 10.3907 = 59.99 mis V = 60 m/s
Transcribed Image Text:Given data. - h = height of the tree = 28 m 8 = angle of projection of ball = 23° Required - V = minimum speed the ball would need to - have hit by the club to make it over the tree We will find the answer using formula sin = sin(23⁰) = 0.3907 Sin = 0.3907 Let Vy C minimum value of Velocity = (2gxh) 1/2) the standard component of Vy = (2gxh) 1/² Vy = (2x 9,81 m/s² x 28m) 1/2 vy = 23.438 m/s =23,438m/s Let V = minimum speed of the ball would need to have hit by the club to make it over the tree V= 1 = Vy / sine = 23.438 m/s 10.3907 = 59.99 mis V = 60 m/s
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