Two biochemical reactions have the same Keq = 5 × 108 at temperature T1 = 298 K. However, Reaction 1 has ΔH° = −28 kJ · mol−1 and Reaction 2 has ΔH° = +28 kJ · mol−1. The two reactions utilize the same reactants. Your lab partner has proposed that you can get more of the reactants to proceed via Reaction 2 rather than Reaction 1 by lowering the temperature of the reaction. Will this strategy work? Why or why not? How much would the temperature have to be raised or lowered in order to change the value of K2 /K1 from 1 to 10?
Two biochemical reactions have the same Keq = 5 × 108 at temperature T1 = 298 K. However, Reaction 1 has ΔH° = −28 kJ · mol−1 and Reaction 2 has ΔH° = +28 kJ · mol−1. The two reactions utilize the same reactants. Your lab partner has proposed that you can get more of the reactants to proceed via Reaction 2 rather than Reaction 1 by lowering the temperature of the reaction. Will this strategy work? Why or why not? How much would the temperature have to be raised or lowered in order to change the value of K2 /K1 from 1 to 10?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Two biochemical reactions have the same Keq = 5 × 108 at temperature T1 = 298 K. However, Reaction 1 has ΔH° = −28 kJ · mol−1 and Reaction 2 has ΔH° = +28 kJ · mol−1. The two reactions utilize the same reactants. Your lab partner has proposed that you can get more of the reactants to proceed via Reaction 2 rather than Reaction 1 by lowering the temperature of the reaction. Will this strategy work? Why or why not? How much would the temperature have to be raised or lowered in order to change the value of K2 /K1 from 1 to 10?
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