This is question.Two analysts measure the percentage of ammonia in a chemical process over9 days and find the following discrepancies between their results:Day123456789Analyst A 12.04 12.37 12.35 12.43 12.34 12.36 12.48 12.33 12.33Analyst B 12.18 12.37 12.38 12.36 12.47 12.48 12.57 12.28 12.42Investigate the mean discrepancy between their results and in particular givean interval in which you are 90% sure that it lies.The answer I got is. Can you please interpret the answer?1. Mean difference w 0.053, S = 0.0498, s = 0.0789. Assuming a standardreference prior for and a variance known equal to 0.07892, the posterior distributionof the effect of Analyst A over Analyst B is N(0.053, 0.07892/9) leading to a 90%interval 0.053 ± 1.6449 × 0.0789/3, that is, (0.010, 0.097). If the variance notassumed known then the normal distribution should be replaced by tg.

The measurements of the percentage of ammonia in a chemical process over 9 days by Analysts A and B…

Answered: Two analysts measure the percentage of…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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