**Problem Statement:**Two 700-kg masses (1543 lb) are separated by a distance of 30 m. Using Newton's law of gravitation, find the magnitude of the gravitational force exerted by one mass on the other. (Use \( G = 6.67 \times 10^{-11} \, \text{N} \cdot \text{m}^2/\text{kg}^2 \).) (Round the final answer to four decimal places.)The magnitude of the gravitational force exerted by one mass on the other is \(\boxed{3.631 \times 10^{-9}}\) N.**Explanation:**Newton's law of gravitation states that the force \( F \) between two masses \( m_1 \) and \( m_2 \), separated by a distance \( r \), is given by:\[ F = \frac{G \cdot m_1 \cdot m_2}{r^2} \]Where:- \( G \) is the gravitational constant, \( 6.67 \times 10^{-11} \, \text{N} \cdot \text{m}^2/\text{kg}^2 \).- \( m_1 \) and \( m_2 \) are the masses, each 700 kg.- \( r \) is the separation distance, 30 m.Substitute the given values into the equation to find the gravitational force.

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Two 700-kg masses (1543 lb) are separated by a distance of 30 m. Using Newton's law of gravitation, find the magnitude of the gravitational force exerted by one mass on the other. (Use G = 6.67 x 10" N-m-/kg².) (Round the final answer to four decimal places.) The magnitude of the gravitational force exerted by one mass on the other is 3.631 x 10-9 N.

Two 700-kg masses (1543 lb) are separated by a distance of 30 m. Using Newton's law of gravitation, find the magnitude of the gravitational force exerted by one mass on the other. (Use G = 6.67 x 10" N-m-/kg².) (Round the final answer to four decimal places.) The magnitude of the gravitational force exerted by one mass on the other is 3.631 x 10-9 N.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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