Two 2.0-cm-diameter disks spaced 1.5 mm apart form a parallel-plate capacitor. The electric field between the disks is 5.0 x 105 V/m. b. How much charge is on each disk? c. An electron is launched from the negative plate. It strikes the positive plate at a speed of 2.0 x 107 m/s. What was the electron’s speed as it left the negative plate

University Physics Volume 2
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Chapter7: Electric Potential
Section: Chapter Questions
Problem 37P: The electric field strength between two parallel conducting plates separated by 4.00 cm is 7.50104...
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Two 2.0-cm-diameter disks spaced 1.5 mm apart form a parallel-plate capacitor. The electric field between the disks is 5.0 x 105 V/m.


b. How much charge is on each disk?
c. An electron is launched from the negative plate. It strikes the positive plate at a speed of 2.0 x 107 m/s. What was the electron’s speed as it left the negative plate?

Expert Solution
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Givendiameter, d=2 cmradius, r=1 cmseparation , t=1.5 mmE=5×105 V/mcapacitance, C=otwhere A is area of plate,t is separationC=ot   =π×10-2 m2×8.85×10-121.5×10-3m   =1.85×10-13 F

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