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3. A proton enters an electric field between two charged plates as shown in the diagram. The proton is
accelerated by a potential difference of 1500 V and exits the field with a velocity of 7.8 x 104 m/s.
What was the original velocity of the proton as it entered the electric field?
-750 V
+750 V
V; = ?
v, = 7.8x10" m/s
proton

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