3. A proton enters an electric field between two charged plates as shown in the diagram. The proton is accelerated by a potential difference of 1500 V and exits the field with a velocity of 7.8 x 10ª m/s. What was the original velocity of the proton as it entered the electric field? -750 V +750 V 7.8x10* m/s proton

icon
Related questions
Question
3. A proton enters an electric field between two charged plates as shown in the diagram. The proton is
accelerated by a potential difference of 1500 V and exits the field with a velocity of 7.8 x 104 m/s.
What was the original velocity of the proton as it entered the electric field?
-750 V
+750 V
V; = ?
v, = 7.8x10" m/s
proton
Transcribed Image Text:3. A proton enters an electric field between two charged plates as shown in the diagram. The proton is accelerated by a potential difference of 1500 V and exits the field with a velocity of 7.8 x 104 m/s. What was the original velocity of the proton as it entered the electric field? -750 V +750 V V; = ? v, = 7.8x10" m/s proton
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps

Blurred answer