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Tutoriar Exercise Consider the following figure. 7.00 N 4.00 N 9.00 R a b (a) Find the equivalent resistance between points and b in the figure. (R = 15.5 N) (b) Calculate the current in each resistor if a potential difference of 27.0 V is applied between points a and b.

Tutoriar Exercise Consider the following figure. 7.00 N 4.00 N 9.00 R a b (a) Find the equivalent resistance between points and b in the figure. (R = 15.5 N) (b) Calculate the current in each resistor if a potential difference of 27.0 V is applied between points a and b.

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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Tutorial Exercise Consider the following figure. 7.00 N 4.00 N 9.00 N R a b (a) Find the equivalent resistance between points a and b in the figure. (R = 15.5 2) (b) Calculate the current in each resistor if a potential difference of 27.0 V is applied between points a and b. Step 1 (a) The 7.00-N and the R = 15.5 2 resistors between points c and d in the figure above are connected in parallel with each other. Thus we can redraw the figure, as shown in the diagram below where Red is the equivalent resistance between points c and d in the original figure. 4.00 N Red 9.00 N
Transcribed Image Text:Tutorial Exercise Consider the following figure. 7.00 N 4.00 N 9.00 N R a b (a) Find the equivalent resistance between points a and b in the figure. (R = 15.5 2) (b) Calculate the current in each resistor if a potential difference of 27.0 V is applied between points a and b. Step 1 (a) The 7.00-N and the R = 15.5 2 resistors between points c and d in the figure above are connected in parallel with each other. Thus we can redraw the figure, as shown in the diagram below where Red is the equivalent resistance between points c and d in the original figure. 4.00 N Red 9.00 N
Step 1 (a) The 7.00-N and the R = 15.5 2 resistors between points c and d in the figure above are connected in parallel with each other. Thus we can redraw the figure, as shown in the diagram below where Red is the equivalent resistance between points c and d in the original figure. 4.00 N Red 9.00 N For the equivalent resistance, we have -1 1 Rcd = Ω. 7.00 N Ω This resistance is in series with the 4.00-2 and the 9.00-2 resistors as shown in the diagram in this step. Let R, represent the 4.00-2 resistance and Ro the 9.00-2 resistance. The total resistance Rh between points a and b is then Rab = R4 + Rcd + R9 =4.00 Ω+ 2 + 9.00 Q = Ω. Submit Skip (you cannot come back) Need Heln? Read It
Transcribed Image Text:Step 1 (a) The 7.00-N and the R = 15.5 2 resistors between points c and d in the figure above are connected in parallel with each other. Thus we can redraw the figure, as shown in the diagram below where Red is the equivalent resistance between points c and d in the original figure. 4.00 N Red 9.00 N For the equivalent resistance, we have -1 1 Rcd = Ω. 7.00 N Ω This resistance is in series with the 4.00-2 and the 9.00-2 resistors as shown in the diagram in this step. Let R, represent the 4.00-2 resistance and Ro the 9.00-2 resistance. The total resistance Rh between points a and b is then Rab = R4 + Rcd + R9 =4.00 Ω+ 2 + 9.00 Q = Ω. Submit Skip (you cannot come back) Need Heln? Read It
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