12.0 N 4.00 N W 5.00 N 6.00 Ω 8.00 Ω (a) Find the equivalent resistance between point a and b. 11.67 (b) If a voltage of 35.8 V is applied between points a and b, find the current in each resistor. 12 N Your response differs significantly from the correct answer. Rework your solution from the b 5.967 Your response differs from the correct answer by more than 100%. A 7.16 Your response differs from the correct answer by more than 100%. A 8.95 Your response differs from the correct answer by more than 100%. A 4.475 5Ω Your response differs from the correct answer by more than 100%. A

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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Consider the combination of resistors shown in the figure below.
12.0 N
4.00 N
W
5.00 N
6.00 Q
8.00 0
(a) Find the equivalent resistance between point a and b.
11.67
(b) If a voltage of 35.8 V is applied between points a and b, find the current in each resistor.
12 N
Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. A
5.967
Your response differs from the correct answer by more than 100%. A
7.16
Your response differs from the correct answer by more than 100%. A
8.95
Your response differs from the correct answer by more than 100%. A
4.475
Your response differs from the correct answer by more than 100%. A
Transcribed Image Text:Consider the combination of resistors shown in the figure below. 12.0 N 4.00 N W 5.00 N 6.00 Q 8.00 0 (a) Find the equivalent resistance between point a and b. 11.67 (b) If a voltage of 35.8 V is applied between points a and b, find the current in each resistor. 12 N Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. A 5.967 Your response differs from the correct answer by more than 100%. A 7.16 Your response differs from the correct answer by more than 100%. A 8.95 Your response differs from the correct answer by more than 100%. A 4.475 Your response differs from the correct answer by more than 100%. A
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