Tutorial Exercise Solve the differential equation and initial condition and verify that your answer satisfies both the differential equation and the initial condition. Jry = 2x 4 Step 1 The first step is to rewrite the equation with the differential as y2Y = 2x. Now, separate the variables with all functions of y (including the differential dy) alone on one side of the equation and the constant and all functions of x (including dx) on the pther side. Doing this, we get dx y? dy = 2x dx. 2x Step 2 Next, we integrate both sides of our equation using the Power Rule. 2x dx + C
Tutorial Exercise Solve the differential equation and initial condition and verify that your answer satisfies both the differential equation and the initial condition. Jry = 2x 4 Step 1 The first step is to rewrite the equation with the differential as y2Y = 2x. Now, separate the variables with all functions of y (including the differential dy) alone on one side of the equation and the constant and all functions of x (including dx) on the pther side. Doing this, we get dx y? dy = 2x dx. 2x Step 2 Next, we integrate both sides of our equation using the Power Rule. 2x dx + C
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![Tutorial Exercise
Solve the differential equation and initial condition and verify that your answer satisfies both the differential equation and the initial condition.
Sv²y = 2x
= 4
Step 1
The first step is to rewrite the equation with the differential as y2Y = 2x. Now, separate the variables with all functions of y (including the
differential dy) alone on one side of the equation and the constant and all functions of x (including dx) on the pther side. Doing this, we get
dx
y² dy = 2x
dx.
2x
Step 2
Next, we integrate both sides of our equation using the Power Rule.
2x dx
+ C](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2306e68b-a485-4a2a-8733-f190a3a60295%2F4d730400-550c-4316-9716-506a968d844b%2Fgshqg_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Tutorial Exercise
Solve the differential equation and initial condition and verify that your answer satisfies both the differential equation and the initial condition.
Sv²y = 2x
= 4
Step 1
The first step is to rewrite the equation with the differential as y2Y = 2x. Now, separate the variables with all functions of y (including the
differential dy) alone on one side of the equation and the constant and all functions of x (including dx) on the pther side. Doing this, we get
dx
y² dy = 2x
dx.
2x
Step 2
Next, we integrate both sides of our equation using the Power Rule.
2x dx
+ C
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