Tutorial Exercise Find the sum. 4(k + 1)²(k – 4) k = 0 Step 1 Recall the definition of summation notation. az + az + a4 + ... k = 1 For the given problem, k begins with 0 and ends with 3. Therefore, 4(k + 1)2(k – 4) is the sum of 4 4 terms in this series, k = 0 Step 2 Write the terms of the summation. E 4(k + 1)2(k – 4) = {4c0 + 1)²co – - 4)} + {«(1 + 1)²([ ]× - 4)} + {4(2 + 1)?(2- - 4)} + {«c[ ]× +1)² ([ ]x - 4)} k = 0

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