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Cs101, and 30 have taken CS102. 18 students have taken both. How many students are there 2. Suppose that every student in class has taken either CS101 or CS102. 45 students have taken 1. Compute the value of each of these sums. Show the process of computation. Hìnt: You can use the formula: ",2 = n(n + 1)(2n + 1)/6 in one of the questions. 80 30 40 ( a ) Σ (b) Ei/2 + 5) (c) E(2" + 4) i40 i=1 i=1 in class?

Cs101, and 30 have taken CS102. 18 students have taken both. How many students are there 2. Suppose that every student in class has taken either CS101 or CS102. 45 students have taken 1. Compute the value of each of these sums. Show the process of computation. Hìnt: You can use the formula: ",2 = n(n + 1)(2n + 1)/6 in one of the questions. 80 30 40 ( a ) Σ (b) Ei/2 + 5) (c) E(2" + 4) i40 i=1 i=1 in class?

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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**Problem 1: Compute the value of each of these sums. Show the process of computation.** (a) \(\sum_{i=40}^{80} i^2\) (b) \(\sum_{i=1}^{40} (i/2 + 5)\) (c) \(\sum_{i=1}^{30} (2^i + 4)\) *Hint: You can use the formula: \(\sum_{i=1}^{n} i^2 = n(n + 1)(2n + 1)/6\) in one of the questions.* **Problem 2: Suppose that every student in class has taken either CS101 or CS102. 45 students have taken CS101, and 30 have taken CS102. 18 students have taken both. How many students are there in class?**
Transcribed Image Text:**Problem 1: Compute the value of each of these sums. Show the process of computation.** (a) \(\sum_{i=40}^{80} i^2\) (b) \(\sum_{i=1}^{40} (i/2 + 5)\) (c) \(\sum_{i=1}^{30} (2^i + 4)\) *Hint: You can use the formula: \(\sum_{i=1}^{n} i^2 = n(n + 1)(2n + 1)/6\) in one of the questions.* **Problem 2: Suppose that every student in class has taken either CS101 or CS102. 45 students have taken CS101, and 30 have taken CS102. 18 students have taken both. How many students are there in class?**
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