Tutorial Exercise A population of a particular yeast cell develops with a constant relative growth rate of 0.4985 per hour. The initial population consists of 3.2 million cells. Find the population size (in millions of cells) after 3 hours. Step 1 dP Since the relative growth rate is 0.4985 per hour, then the differential equation that models this growth with P in millions of cell and t in hours is = 0.4985P 0.4985P Step 2 We know that P(t) = P(0)ekt, where P(0) is the population on day zero and k is the growth rate, Substitute the values of P(0) and k into P(t) (in millions of cells). P(t) = P(0)ekt million cells 7.1856 million cells %3D Submit Skip (you cannot come back) Need Help? Read It

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Tutorial Exercise
A population of a particular yeast cell develops with a constant relative growth rate of 0.4985 per hour. The initial population consists of 3.2 million cells. Find the population size (in millions
of cells) after 3 hours.
Step 1
dP
= 0.4985P
dt
0.4985P
Since the relative growth rate is 0.4985 per hour, then the differential equation that models this growth with P in millions of cell and t in hours is
Step 2
We know that P(t) = P(0)ekt, where P(0) is the population on day zero and k is the growth rate, Substitute the values of P(0) and k into P(t) (in millions of cells).
P(t) = P(0)ekt million cells
7.1856
million cells
Submit Skip (you cannot come back)
Need Help?
Read It
Transcribed Image Text:-Kipped par Tutorial Exercise A population of a particular yeast cell develops with a constant relative growth rate of 0.4985 per hour. The initial population consists of 3.2 million cells. Find the population size (in millions of cells) after 3 hours. Step 1 dP = 0.4985P dt 0.4985P Since the relative growth rate is 0.4985 per hour, then the differential equation that models this growth with P in millions of cell and t in hours is Step 2 We know that P(t) = P(0)ekt, where P(0) is the population on day zero and k is the growth rate, Substitute the values of P(0) and k into P(t) (in millions of cells). P(t) = P(0)ekt million cells 7.1856 million cells Submit Skip (you cannot come back) Need Help? Read It
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