1986, the Chernobyl nuclear power plant meltdown released Cesium-137 into the urrounding area, making it radioactive for many years to come. Cesium-137 decays at a rate of A(t) = Ae-0.0231t, where A(t) represents the amount of Cesium-137 left after a given time (in kilograms), A, represents the initial amount of Cesium-137 (in kilograms), and t represents the number of years. If the meltdown released 30 kilograms, how many years will it take for the amount of Cesium-137 to get to a safe amount of only 0.25 kilograms in the area?

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section: Chapter Questions
Problem 15T
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In 1986, the Chernobyl nuclear power plant meltdown released Cesium-137 into the
surrounding area, making it radioactive for many years to come. Cesium-137 decays
Aoe-0.0231t
, where A(t) represents the amount of
at a rate of A (t) =
Cesium-137 left after a given time (in kilograms), A, represents the initial amount of
Cesium-137 (in kilograms), and t represents the number of years. If the meltdown
released 30 kilograms, how many years will it take for the amount of Cesium-137 to
get to a safe amount of only 0.25 kilograms in the area?
Transcribed Image Text:In 1986, the Chernobyl nuclear power plant meltdown released Cesium-137 into the surrounding area, making it radioactive for many years to come. Cesium-137 decays Aoe-0.0231t , where A(t) represents the amount of at a rate of A (t) = Cesium-137 left after a given time (in kilograms), A, represents the initial amount of Cesium-137 (in kilograms), and t represents the number of years. If the meltdown released 30 kilograms, how many years will it take for the amount of Cesium-137 to get to a safe amount of only 0.25 kilograms in the area?
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