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Tungsten (W) metal, used to make incandescent light-bulb filaments, is produced by the reaction   WO3(s) + 3H2(g)   --->   W(s) + 3H2O(l)   Based on this equation, how many grams of WO3 is needed to produce each of the following?   10.00 g of W 1 billion (1.00 x 109) molecules of H2O 53 moles of H2O 250,000 atoms of W

Tungsten (W) metal, used to make incandescent light-bulb filaments, is produced by the reaction   WO3(s) + 3H2(g)   --->   W(s) + 3H2O(l)   Based on this equation, how many grams of WO3 is needed to produce each of the following?   10.00 g of W 1 billion (1.00 x 109) molecules of H2O 53 moles of H2O 250,000 atoms of W

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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  1. Tungsten (W) metal, used to make incandescent light-bulb filaments, is produced by the reaction

 

WO3(s) + 3H2(g)   --->   W(s) + 3H2O(l)

 

Based on this equation, how many grams of WO3 is needed to produce each of the following?

 

  1. 10.00 g of W
  2. 1 billion (1.00 x 109) molecules of H2O
  3. 53 moles of H2O
  4. 250,000 atoms of W
Tungsten (W) metal, used to make incandescent light-bulb filaments, is produced by the reaction: \[ \text{WO}_3(s) + 3\text{H}_2(g) \rightarrow \text{W}(s) + 3\text{H}_2\text{O}(l) \] Based on this equation, how many grams of WO\(_3\) are needed to produce each of the following? a. 10.00 g of W b. 1 billion (1.00 x 10\(^9\)) molecules of H\(_2\)O c. 2.53 moles of H\(_2\)O d. 250,000 atoms of W
Transcribed Image Text:Tungsten (W) metal, used to make incandescent light-bulb filaments, is produced by the reaction: \[ \text{WO}_3(s) + 3\text{H}_2(g) \rightarrow \text{W}(s) + 3\text{H}_2\text{O}(l) \] Based on this equation, how many grams of WO\(_3\) are needed to produce each of the following? a. 10.00 g of W b. 1 billion (1.00 x 10\(^9\)) molecules of H\(_2\)O c. 2.53 moles of H\(_2\)O d. 250,000 atoms of W
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