**Title: Calculating Moles of Ammonia (NH₃) Produced from Nitrogen****Objective:** Determine the moles of ammonia (NH₃) producible from 2.66 moles of nitrogen (N₂) using the given chemical reaction.**Chemical Reaction:**\[ \text{N}_2 (g) + 3 \text{H}_2 (g) \rightarrow 2 \text{NH}_3 (g) \]**Explanation:**In this balanced chemical equation, one mole of nitrogen gas (\(\text{N}_2\)) reacts with three moles of hydrogen gas (\(\text{H}_2\)) to produce two moles of ammonia gas (\(\text{NH}_3\)).To find out how many moles of ammonia can be produced from 2.66 moles of nitrogen, use the molar ratio from the balanced equation:1 mole of \(\text{N}_2\) produces 2 moles of \(\text{NH}_3\).**Calculation:**\[ 2.66 \, \text{moles of} \, \text{N}_2 \times \frac{2 \, \text{moles of} \, \text{NH}_3}{1 \, \text{mole of} \, \text{N}_2} = 5.32 \, \text{moles of} \, \text{NH}_3 \]**Conclusion:**From 2.66 moles of nitrogen, 5.32 moles of ammonia can be produced, assuming there is enough hydrogen gas present to complete the reaction.

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How many moles of NH3 can be produced from 2.66 moles of nitrogen in the following reaction: N2 (g) + 3 H2 (g) → 2 NH3 (g)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Stoichiometry

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Question

**Title: Calculating Moles of Ammonia (NH₃) Produced from Nitrogen**

**Objective:** Determine the moles of ammonia (NH₃) producible from 2.66 moles of nitrogen (N₂) using the given chemical reaction.

**Chemical Reaction:**

\[ \text{N}_2 (g) + 3 \text{H}_2 (g) \rightarrow 2 \text{NH}_3 (g) \]

**Explanation:**

In this balanced chemical equation, one mole of nitrogen gas (\(\text{N}_2\)) reacts with three moles of hydrogen gas (\(\text{H}_2\)) to produce two moles of ammonia gas (\(\text{NH}_3\)).

To find out how many moles of ammonia can be produced from 2.66 moles of nitrogen, use the molar ratio from the balanced equation:

1 mole of \(\text{N}_2\) produces 2 moles of \(\text{NH}_3\).

**Calculation:**

\[ 2.66 \, \text{moles of} \, \text{N}_2 \times \frac{2 \, \text{moles of} \, \text{NH}_3}{1 \, \text{mole of} \, \text{N}_2} = 5.32 \, \text{moles of} \, \text{NH}_3 \]

**Conclusion:**

From 2.66 moles of nitrogen, 5.32 moles of ammonia can be produced, assuming there is enough hydrogen gas present to complete the reaction.

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