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- This question has multiple parts. Work all the parts to get the most points. The following reaction occurs in two steps. HI Predict the organic intermediate(s) and product(s), and provide the mechanism for the reaction. a.1 Draw the organic intermediate formed after the first step of this reaction. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. • You do not have to consider stereochemistry. Do not include counter-ions, e.g., Na+, I-, in your answer. • Do not include lone pairs in your answer. They will not be considered in the grading. Ө ? ChemDoodle >Predict the products of this organic reaction: & + Explanation NH₂ Check H3O+ • Draw all the reasonable products in the drawing area below. If there are no products, because no reaction will occur, check the box under the drawing area. ? • Include both major and minor products, if some of the products will be more common than others. • Be sure to use wedge and dash bonds if you need to distinguish between enantiomers. Click and drag to start drawing a structure. C C X Ś cx ? olo Ar 8. KJplease help and draw answer and circle the answer
- The major product of this reaction exists as two stereoisomers. Draw both isomers. Show all hydrogen atoms in the structures. Use wedge and dash bonds to indicate the stereochemistry. H XE CH3 (large H3C H3C-CH₂ Br-Br H₂O excess) You can quickly add condensed hydrogens by clicking the More button and using the +H button. Select Draw Rings More EraseA student wants to synthesize propionitrile from ethanol. CH₂CH₂OH CH₂CH₂CN Which of these reagents would work? (Select all that apply). 1. HBr 2. NaCN 1. SOCI₂, pyridine 2. NaCN 1. PBr3, pyridine 2. NaCNplease help solve
- pls help with both questions1,3-Butadiene undergoes an electrophilic addition with HBr. Complete the steps in the mechanism to produce the product shown. HBr Br 2) Draw both the organic and inorganic intermediate species. Include all nonbonding 1) Add curved arrows for the first step. Select Draw Rings More Erase electrons and charges. Draw a curved arrow to convert this intermediate into the more stable C H Br intermediate shown by resonance. Select Draw Rings More Erase H Br .. Br : ↑Nitesh
- For the given SN2 reaction, draw the organic and inorganic products of the reaction, and identify the nucleophile, substrate, and leaving group. Include wedge-and-dash bonds and draw hydrogen on a stereocenter. Him... CEN + CI Draw the organic product. Select Draw Templates More C HN C Organic product Inorganic product Draw the inorganic product. Erase Select Draw Templates More ////// C H N Cl EraseThe major product of this reaction exists as two stereoisomers. Draw both isomers. Show all hydrogen atoms in the structures. Use wedge and dash bonds to indicate the stereochemistry. You can quickly add condensed hydrogens by clicking the More button and using the +H button. Select Draw Rings More Erase H Br H3C-CH2 H Br-Br H20 H3C CH3 (large excess) > Feedback First, an electrophilic attack of bromine on the double bond results in the formation of a bromonium ion. Next, a nucleophilic attack of water opens the bromonium ion ring. The product of the reaction is a halohydrin. Consider regiochemistry and stcrcochemistry. 1. Will the intermediate ion be more stable with a positive charge on a tertiary carbon, or on a secondary carbon? 2. Which carbon in the bromonium ring will be attacked by water? 3. In the product, what group is added to the more substituted carbon of the double bond? To the less substituted carbon? Do not forget that you nccd to draw two stcrcoisomcrs of the product.…Question 3 a) Penta-2,4-diene has 2 geometric isomers. Skeletally draw and name these isomers. b) When penta-1,4-diene reacts with HBr in an electrophilic addition reaction, 3 products are formed. Draw the 3 products of this reaction skeletally and identify the major product. c) Sketch the mechanism of the reaction which forms the major product. You must show any relevant bond dipoles. d) Sketch of the product of the electrophilic addition reaction of penta-1,4-diene with Br2 skeletally. Why is there just one product in this case?