Triangle: A = base × Height Square: A = s²; s = lenght of side Regular Hexagon with Apothem: A = 1/san where; s= lenght of side n = number of sides of a polygon - a = apothem Apothem is the perpendicular distance from the center of the regular polygon to any o the side. apothem Formula: a = -tan (™(2-2)) (radian mode) 2n Note: In degree mode π = 180°
Triangle: A = base × Height Square: A = s²; s = lenght of side Regular Hexagon with Apothem: A = 1/san where; s= lenght of side n = number of sides of a polygon - a = apothem Apothem is the perpendicular distance from the center of the regular polygon to any o the side. apothem Formula: a = -tan (™(2-2)) (radian mode) 2n Note: In degree mode π = 180°
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
Related questions
Question
Explain me how to get the answers for
Area of triangle
Area of Pentagon
Area of Hexagon
![Area of regular Polygons
Triangle: A = base x Height
Square: A = s²; s = lenght of side
Regular Hexagon with Apothem: A =
where; s = lenght of side
2
Apothem -
the side.
n = number of sides of a polygon
san
a = apothem
- is the perpendicular distance from the center of the regular polygon to any of
T(n-2)
2n
Formula: a = tan
Note: In degree mode = 180°
apothem
(radian mode)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcd5f13eb-ed8c-423c-bde9-7b5460fc42c5%2F0eab2068-d550-4175-b625-c56cbeb1830e%2F5rgnj27_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Area of regular Polygons
Triangle: A = base x Height
Square: A = s²; s = lenght of side
Regular Hexagon with Apothem: A =
where; s = lenght of side
2
Apothem -
the side.
n = number of sides of a polygon
san
a = apothem
- is the perpendicular distance from the center of the regular polygon to any of
T(n-2)
2n
Formula: a = tan
Note: In degree mode = 180°
apothem
(radian mode)
![Area of Pentagon
Solution: Since the perimeter is 12, hence
S = 12 + 5 = 2.4 inches
Area:
apothem = tan ((2-2)
2.4
= 2/+tan (T(5-²))
a =
a = (1.2) tan
a = 1.6517 inches
a =
a = (1) tan
3T
Area of Hexagon
Solution: Since the perimeter is 12, hence
S = 12 + 6 = 2 inches
Area:
apothem = tan ((n=2))
= ²tan ((6-2))
4πT
a = tan
a = √3 inches
A = san =
=
P(a)
2
A = (2.4)(1.6517) (5)
A = 9.9102 sq. inches
A =
apothem
= 1/san
A = ²(2)(√3)(6)
A = 10.3923 sq. inches
apothem](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcd5f13eb-ed8c-423c-bde9-7b5460fc42c5%2F0eab2068-d550-4175-b625-c56cbeb1830e%2Foaswmzn_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Area of Pentagon
Solution: Since the perimeter is 12, hence
S = 12 + 5 = 2.4 inches
Area:
apothem = tan ((2-2)
2.4
= 2/+tan (T(5-²))
a =
a = (1.2) tan
a = 1.6517 inches
a =
a = (1) tan
3T
Area of Hexagon
Solution: Since the perimeter is 12, hence
S = 12 + 6 = 2 inches
Area:
apothem = tan ((n=2))
= ²tan ((6-2))
4πT
a = tan
a = √3 inches
A = san =
=
P(a)
2
A = (2.4)(1.6517) (5)
A = 9.9102 sq. inches
A =
apothem
= 1/san
A = ²(2)(√3)(6)
A = 10.3923 sq. inches
apothem
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