QUESTION 16Match the correct choices with the given.For gravimetric analysis, use this data to answer the questions.|Trial 10.6020 g24.8405 g24.8451 g24.8422Trial 20.5021 g22.8165 g22.8165 gTrial 30.5018 g22.8169 g22.8169 g|Weight of SampleWeight of Crucible and Ba$O,824.8422 gConstant Weight of Crucible &Sample24.8422 g 22.8165 g22.8169 gWeight of Crucible24.318122.3593 g22.3641 g24.3160 g24.3142 g24.3142 g24.3142 g24.3142 g22.3523 g22.3534 g22.3532 g22.3532 g22.3612 g22.3605 g22.3605 g22.3605 gConstant Weight of Crucible22.3532 g22.3605 gWeight of BaSo,|% so,2-AverageStandard deviationRelative standard deviationA. 2.65Average of the % (w/w) SO42-B. to decompose the solid and form acompound of known composition and toremove the solvent and any non-volatilespeciesStandard deviation of the % (w/w)So2-Relative standard deviation of theC. reprecipitation% (w/w) SO42-D. formation of small crystalsThis is a drastic but effective wayto minimize the effects ofE. 37.18 % (w/w)F. 2.13G. for its mass to be lower and performadsorbed impuritiesThe possible reasons for theignition of gravimetric precipitatepost-precipitationareH. 0.79Dropwise addition of theprecipitating agents leads toI. formation of large crystals

Since you have posted a question with multiple sub-parts, we will solve first three subparts for…

Trial 1 Trial 2 Trial 3 0.6020 g 24.8405 g 24.8451 g 24.8422 g 24.8422 g 0.5021 g 22.8165 g 22.8165 g Weight of Sample Weight of Crucible and BasO. 0.5018 g 22.8169 g 22.8169 g Constant Weight of Crucible & Sample 24.8422 g 22.8165 g 22.8169 g

Trial 1 Trial 2 Trial 3 0.6020 g 24.8405 g 24.8451 g 24.8422 g 24.8422 g 0.5021 g 22.8165 g 22.8165 g Weight of Sample Weight of Crucible and BasO. 0.5018 g 22.8169 g 22.8169 g Constant Weight of Crucible & Sample 24.8422 g 22.8165 g 22.8169 g

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

A compound with the empirical formula 2 was found to have a mo- lar mass of approximately 84 g. Write the molecular formula of the compound. Answer in a complete sentence. Be sure to show your work. | I H Normal + == A A CH Enter your answer here = = = = | B I US Ⓒ √x Q 0 T X₂ X²
ERROR ANALYSIS A student solving the problem based on the scenario below made an error and the answer is incorrect for percent by mass. Identify the error and solve the problem to determine the correct answer. Calculate the percent by mass of vinegar in a lab grade bottle when the mass of the vinegar in the bottle is 150.0 g and the mass of water in the bottle is 449.35 g. percentby mass = _Massofsolute Kl00 Massofsdlution pereent bymass = 150.0g Xl00 449.359 = 33.38% vinegar percent by mass
Can somebody help me with this problem by explaining the transition there at the bottom? How it went 2.468.. to 11.8025?
What did you see when you peeked inside your crucible
Exit Submit What mass of sodium fluoride (used in water fluoridation and the manufacture of insecticides) is required to form 485 g of sulfur tetrafluoride? 3SCI2() + 4NAF(s)SF4(g) + S2CI2() - 4N2CI(s) Multiple Choice 1.94 kg 1.51 kg 205 g 2:43 11-Mar asus COLLECTION prt sc delete no 112/A f8 & Q
1.008 4.003 3. 6. 10 LI Be B Ne 6.941 9.012 10.81 12.01 14.01 16.00 19.00 20.18 15 13 14 16 12 Na Mg 22 99 24.31 11 17 18 Al SI Ar 26.98 28.09 3097 32.0735.453995 20 24 30 32 31 Zn Ga Ge 33 34 22 TI 19 21 23 25 26 27 28 Co Cu 29 35 Br 36 Kr KCa 39 10 40 08 44 96 47 8850.94 52.00 54 94 55 85 SS 93 58.69 63.55 65 38 69 7272 59 2492 789679 90 83 80 Se Cr Mn Fe As Se 37 38 39 40 45 46 47 Rh Pd Ag 49 50 Cd In Sn 41 42 44 52 53 54 Xe 8547 87.62 88919122 92 91 9594 (98) 1011 102:9 10641oig112.1148 118712181276126.9 131 3 $5 43 Rb Sr Zr Nb Mo Te Ru Sb Te 73 74 75 76 Re 77 78 Ir Pt 55 56 57 72 84 $1 $2 TI Pb $3 $6 Cs Ba La Ta Os Au Hg Bi Po At Rn 132 9 1373 139 9178 5180 9|183.9|186 21902i9aai19stlor.db00 6/204.42072209 0209)210222) 87 S$ 89 223) 226 (227) Fr Ra Ac Question 10 /10 ميز هذا السؤال A solution is prepared by dissolving 0.258 grams on magnesium chloride (MgCl, ) in water to produce 250.0 mL of solution. Calculate the molarity of the chloride ion in the solution. 1. 00.271 Molar 2.…
H He 1.008 3 4.003 36 7 S 9 10 4 C Li Be 6.941 9.012 B F Ne 10.81 12.01 14.01 16.00 19.00 20.18 13 14 Al Si 26.98 28.09 30.97 32.07 35.45 39 95 15 16 17 S 11 12 18 Na Mg 22.99 24.31 Ar 26 27 28 Co 39.10 40.08 44.96 47.88 50.94 52.00 54.94 55.85 58.93 58.69 63.5s|65.38 69.72 72.59 74.92 78.96 79.90 83.80 22 23 24 25 Cr 19 20 21 29 30 31 32 33 34 35 36 K Ca Sc Ti Mn Fe Ni Cu Zn Ga Ge As Se Br Kr 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 |Y Zr Te ca In Sn Sb Te I Rb Sr Nb Мо Ru Rh Pd Ag Cd Xe 85.47 87.62 88.91 91.22 92.9195.94 (98) 101.1 102.9 106.4 107.9 112.4 114.8 118.7 121.8127.6 126.9 1313 55 56 57 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 Cs Ba Ва La Hf Ta Re Os Ir Pt Au Hg TI Pb Bi Po At Rn 132.9 137.3 138 9178.5 180.9 183.9 186.2 190.2 192.2 195.1 197.0 200.6 204.4 207.2 209.0 (209) (210) (222) 87 89 Fr Ra Ac (223) 226 (227) Calculate the pH of a 50.00 mL of 0.2000 M ammonia (Ka = 5.7 x 10-10) solution after addition of 50.00 mL of 0.2000 M HCl in the titration. 1.…
%24 4+ dl w/ b. Be sure to answer all parts. How many moles are contained in each number of grams of table sugar (C12H22011, molar mass 342.3 g/mol)? Enter your answer in scientific notation. a. 55.0 g b. 0.0250 g x 10 mol x 10 IIO %23 2 3. 5. 9- 8. 4
Imole 1,5g Cu 504,3 X Imole ('u 5 0415H20 = Moles of anhydride used. (Show calculations) = Cu Soy • 5H20(s) A ('u 504 (5) + 5H20 (9) Hydrate » anhydride Moles of H₂O of hydration (Show calculations)= Ratio of moles of water to moles of anhydride (Show calculations.) = Molarmass = (to correct sig. figs. - do not round yet) Based on your data, what is the empirical formula of your hydrate (round your ratio to the closest whole number)? Use the Argumentation Framework (see inside front cover) (Claim- Evidence- Justification) to justify your answer. 147 S 112 52
A 0.235 mL sample of carbon tetrachloride (density = 1.59 g/mL, MM = 153.81 g/mol) contains how many AMU of Cl? Note: Use 6.022 x 1023 and/or 1.661 x 10-24 as appropriate. 5.18 x 1022 2.42 x 10-3 2.07 x 1020 1.30 x 1022 2.07 x 1023 0.333 g of a hydrocarbon (CxHy) was analyzed by combustion analysis and 1.009 g of CO2 (MM = 44.01 g/mol) and 0.516 g of H2O (MM = 18.02 g/mol). Which of the following is the correct empirical formula of the hydrocarbon? C2H4 C2H5 C3H7 C2H3 CH3
Br Br 2. 1. Mg. Et₂0 3. H3O+ 1. Mg Et₂O 1. Mg Et₂0 2. 3. H3O+ Дон 2. H 3. H3O+ CH3 /Et₂0 0/E1₂0 Et₂0
H 1.008 3 Li 6.94 11 4 Be 9.012 12 Na Mg 22.990 24.305 19 Select one: 5 O a. i and ii O b. i and iii O c. ii only O d. i, ii, and iii 14 16 17 Al Si PS CI Ar 26.982 28.085 30.974 32.06 35.45 31 32 33 34 35 39.948 36 20 21 22 23 24 25 26 27 28 29 30 K Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Kr 39.098 40.078 44.956 47.867 37 38 39 50.942 41 51.996 42 54.938 43 55.845 44 58.933 45 58.693 63.546 65.38 69.723 72.630 74.922 78.971 79.904 83.798 46 47 48 49 50 51 52 53 54 40 Rb Sr Y Zr Nb Mo Tc 85.468 87.62 88.906 91.224 92.906 95.95 [97] 101.07 102.91 106.42 107.87 112.41 114.82 118.71 121.76 127.60 126.90 131.29 Ru Rh Pd Ag Cd In Sn Sb Te I Xe Which of the following will have an odd number of electrons in their 3d orbital? i. Cr²+ ii. Mn²+ iii. Fe²+ 10.81 6 BC с 13 8 9 10 NO F Ne 12.011 14.007 15.999 18.998 20.180 15 He 4.003 7 18 18 e