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Trial 1 d=(Vf+Vi/2)t d/t*2- Vf= Vi (24/5.50) x 2-0 = 8.7 m/s Trial 2 d=(Vf+Vi/2)t d/t*2- Vf= Vi (28/6.70)x 2-0 = 8.4 m/s Trial 3 d=(Vf + Vi/2)t d/t*2- Vf = Vi (28/6.78)x 2-0 = 8.3 m/s (8.7+8.4+8.3)/3 = 8,46666666667

Trial 1 d=(Vf+Vi/2)t d/t*2- Vf= Vi (24/5.50) x 2-0 = 8.7 m/s Trial 2 d=(Vf+Vi/2)t d/t*2- Vf= Vi (28/6.70)x 2-0 = 8.4 m/s Trial 3 d=(Vf + Vi/2)t d/t*2- Vf = Vi (28/6.78)x 2-0 = 8.3 m/s (8.7+8.4+8.3)/3 = 8,46666666667

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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use the given information below to make a velocity - time graph 

Trial 1 d=(Vf + Vi/2)t d/t*2- Vf Vi (24/5.50) x 2-0 = 8.7 m/s Trial 2 d=(Vf + Vi/2)t d/t *2- Vf = Vi (28/6.70)x 2-0 = 8.4 m/s Trial 3 d=(Vf + Vi/2)t d/t *2- Vf = Vi (28/6.78)x 2-0 = 8.3 m/s (8.7+8.4+8.3)/3 = 8.46666666667
Transcribed Image Text:Trial 1 d=(Vf + Vi/2)t d/t*2- Vf Vi (24/5.50) x 2-0 = 8.7 m/s Trial 2 d=(Vf + Vi/2)t d/t *2- Vf = Vi (28/6.70)x 2-0 = 8.4 m/s Trial 3 d=(Vf + Vi/2)t d/t *2- Vf = Vi (28/6.78)x 2-0 = 8.3 m/s (8.7+8.4+8.3)/3 = 8.46666666667
Trial # Trial 1 Trial 2 Trial 3 Average Time Average Distance Average Speed Time 5.50 s 6.70 s 6.78 s Distance 24 m 28 m 28 m (T1+T2+T3) / 3 = Average Time 5.50 +6.70 +6.78/3= 6.33 s (D1+D2+D3)/3 = Average Distance 24+28+28/3= 26.66 m (S1+S2+S3)/3 = Average Speed 4.363+ 4.179 + 4.129/3= Speed Speed = Distance/Time 24 M/5.50 S Speed of trial 1 = 4.363 m/s Speed= Distance/Time 28 M/6.70 S Speed of trial 2 = 4.179 m/s Speed = Distance/Time 28 M/6.78 S Speed of trial 3 4.129 m/s
Transcribed Image Text:Trial # Trial 1 Trial 2 Trial 3 Average Time Average Distance Average Speed Time 5.50 s 6.70 s 6.78 s Distance 24 m 28 m 28 m (T1+T2+T3) / 3 = Average Time 5.50 +6.70 +6.78/3= 6.33 s (D1+D2+D3)/3 = Average Distance 24+28+28/3= 26.66 m (S1+S2+S3)/3 = Average Speed 4.363+ 4.179 + 4.129/3= Speed Speed = Distance/Time 24 M/5.50 S Speed of trial 1 = 4.363 m/s Speed= Distance/Time 28 M/6.70 S Speed of trial 2 = 4.179 m/s Speed = Distance/Time 28 M/6.78 S Speed of trial 3 4.129 m/s
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