TReferences) A 19.5 g piece of lead was heated to 97.5 °C in boiling water and then dropped into a beaker containing 30.7 g of water at 24.4 °C. When the water and metal came to thermal equilibrium, the temperature was 25.8 °C. What is the specific heat capacity of lead? The specific heat capacity of water is 4.184 J/g K. J/g K
TReferences) A 19.5 g piece of lead was heated to 97.5 °C in boiling water and then dropped into a beaker containing 30.7 g of water at 24.4 °C. When the water and metal came to thermal equilibrium, the temperature was 25.8 °C. What is the specific heat capacity of lead? The specific heat capacity of water is 4.184 J/g K. J/g K
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A 19.5 g piece of lead was heated to 97.5 °C in boiling water and then dropped into a beaker containing 30.7 g of water at 24.4 °C. When the water and metal came to thermal equilibrium, the temperature was 25.8 °C. What is the specific heat capacity of lead? The specific heat
capacity of water is 4.184 J/g K.
J/g K
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A 19.5 g piece of lead was heated to 97.5 °C in boiling water and then dropped into a beaker containing 30.7 g of water at 24.4 °C. When the water and metal came to thermal equilibrium, the temperature was 25.8 °C. What is the specific heat capacity of lead? The specific heat
capacity of water is 4.184 J/g K.
J/g K
Submit Answer
Try Another Version
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Expert Solution
Step 1
Given : mass of lead = 19.5 g
Initial temperature of lead = 97.5 oC
Mass of water = 30.7 g
Initial temperature of water = 24.4 oC
And the final temperature of the mixture = 25.8 oC
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