Tree heights: Cherry trees in a certain orchard have heights that are normally distributed with mean u = 113 inches and standard deviation o = 14 inches, Usethe O Cumulative Normal Distribution Table to answer the following.(a) Find the 26" percentile of the tree heights.(b) Find the 84 percentile of the tree heights.(c) Find the second quartile of the tree heights.(d) An agricultural scientist wants to study the tallest 1% of the trees to determine whether they have a certain gene that allows them to grow taller. To do this,she needs to study all the trees above a certain height. What height is this?Round the answers to at least two decimal places.Part: 0 / 4Part 1 of 4The 26" percentile of the tree heights isinches.8Table A.262936664701973577673796782380.469150.5729172570.67611758079390.7791078818212088485818681598461870889070.98438841386861.08665864388881.18869908292361.288499066903290491.392079222149192935793701.59332934594529463947494841.795549564957395821.896419649965696641.9971397729719972697322.09778978397882.19821982622.298619830983498642.39893986898711249896989899182.599209901993899222.699409929994399539941(2.79955996599562.899662.99974995996799769982998799759981 9982996899799813.03.19987 998799909993999599979991999399999949999998

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Answered: Tree heights: Cherry trees in a certain…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The mean is 146 and the standard deviation is 35. A score of 41 is how many z-scores below the mean?
The empirical rule estabilishes the percentages that are 1,2, and 3 deviations from the mean True Flase
The sample mean X is to be used to estimate the mean u of a normal distribution with standard deviation 4 inches. How large a sample should be taken in order chat, with 90% probability, the estimate will be in error by at most one-half inch?
Suppose that water usages in American showers are normally distributed, with an average shower using 17.1 gallons, and a standard deviation of 3.5 gallons. Estimate the percentage of showers that used(a) between 6.6 and 27.6 gallons.__________%(b) more than 27.6 gallons.__________ %(c) less than 13.6 gallons. __________%(d) between 13.6 and 27.6 gallons. __________% Answer the blanks.
Tree heights: Cherry trees in a certain orchard have heights that are normally distributed with mean u = 114 inches and standard deviation a = 15 inches. Use the TI-84 PLUS calculator to answer the following. Round the answers to at least two decimals. (a) Find the 27" percentile of the tree heights. (b) Find the 85 percentile of the tree heights. (c) Find the third quartile of the tree heights. (d) An agricultural scientist wants to study the tallest 2% of the trees to determine whether they have a certain gene that allows them to grow taller. To do this, she needs to study all the trees above a certain height. What height is this?
The heights of adult American men can be modeled by a normal distribution with mean μ = 69 inches and standard deviation σ = 2.5 inches. What height is at the 84th percentile of the distribution?Use the empirical rule and do not round your answer.
The mean score for first exam in your first organic chemistry class (section A) was 60, with a standard deviation of 5. Your score on the exam was 70. A. How many standard deviations above the mean is your score?
Because the mean is very sensitive to extreme values, it is not a resistant measure of center. By deleting some low values and high values, the trimmed mean is more resistant. To find the 10% trimmed mean for a data set, first arrange the data in order, then delete the bottom 10% of the values and delete the top 10% of the values, then calculate the mean of the remaining values. Use axial loads (pounds) of aluminum cans listed below for cans that are 0.0111 in. thick. Identify any outliers, then compare the median, mean, 10% trimmed mean, and 20% trimmed mean. 247 261 269 273 275 280 282 282 284 285 285 287 290 292 293 296 296 299 311 507 Identify any outliers. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. OA. The outlier(s) is/are pounds. (Type a whole number. Use a comma to separate answers as needed.) C OB. There are no outliers.
On an intelligence test, the mean number of raw items correct is 236 and the standard deviation is 39. What are the raw (actual) scores on the test for people with IQs of (a) 119, (b) 81, and (c)100? To do this problem, first figure the Z score for the particular IQ score; then use that Z score to find the raw score. Note that IQ scores have a mean of 100 and a standard deviation of 15. (a) What is the raw (actual) score on the test for people with an IQ of 119?
Bottles for room spray are supposed to weigh exactly 16 oz. Inspectors want to develop process control charts. They take six boxes of five bottles each and weigh them. They obtain the following data. The mean weights of each of the 6 samples are 15.43, 14.47, 18.07, 17.34, 12.74, and 15.58 respectively. Likewise, the range values for the each of 6 samples are 1.63,0.66, 0.47,0.40, 0.20, and 0.90 respectively. Find out Grand Mean (X double bar), and mean range (R bar) O a. 16.538, 0.86 O b. 15.61,0.71 16.53,0.71 O d. 15.82, -0.65 O e. 0,0
Question (g) Compute the three quartiles and draw a box-whisker plot showing therequired calculations.(h) Compute the 29th percentile of the data and interpret its value.
Explain the meaning of the accompanying percentiles. (a) The 5th percentile of the head circumference of males 3 to 5 months of age in a certain city is 41.5 cm. (b) The 95th percentile of the waist circumference of females 2 years of age in a certain city is 49.8 cm. (c) Anthropometry involves the measurement of the human body. One goal of these measurements is to assess how body measurements may be changing over time. The following table represents the standing height of males aged 20 years or older for various age groups in a certain city in 2015. Based on the percentile measurements of the different age groups, what might you conclude?

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